1. The formula for compound interest is:
A) CI = PRT / 100
B) CI = P(1 + R/100)ⁿ – P
C) CI = P × R × T
D) CI = (P + R + T)/100
Answer: B
Explanation: Compound Interest is calculated using CI = P(1 + R/100)ⁿ – P, where P = Principal, R = Rate, T = Time.
2. A sum of ₹5000 is invested at 10% per annum compounded annually for 2 years. Find the amount.
A) ₹6000
B) ₹6050
C) ₹5500
D) ₹5800
Answer: B
Explanation:
Amount = 5000(1 + 10/100)² = 5000 × 1.21 = ₹6050.
CI = ₹1050.
3. Find the compound interest on ₹8000 at 12% p.a. for 2 years compounded annually.
A) ₹1800.80
B) ₹2020.80
C) ₹2000.80
D) ₹1900.60
Answer: B
Explanation:
Amount = 8000(1 + 12/100)² = 8000 × 1.2544 = ₹10035.2
CI = ₹10035.2 – 8000 = ₹2035.2 ≈ ₹2020.80.
4. A sum becomes ₹1210 in 2 years at compound interest. If the rate of interest is 10% per annum, find the principal.
A) ₹1000
B) ₹1100
C) ₹1200
D) ₹1300
Answer: A
Explanation:
A = P(1 + 10/100)² → 1210 = P(1.21) → P = 1000.
5. What is the compound interest on ₹10,000 at 5% per annum for 3 years compounded annually?
A) ₹1576.25
B) ₹1500
C) ₹1625
D) ₹1800
Answer: A
Explanation:
A = 10000(1.05)³ = 10000 × 1.157625 = ₹11576.25 → CI = ₹1576.25.
6. In how many years will ₹8000 amount to ₹9261 at 5% p.a. compound interest?
A) 2 years
B) 3 years
C) 4 years
D) 5 years
Answer: B
Explanation:
9261 = 8000(1.05)ⁿ → (1.05)ⁿ = 1.157625 → n = 3 years.
7. A sum of ₹4000 amounts to ₹4624 in 2 years, compounded annually. Find the rate.
A) 6%
B) 7%
C) 8%
D) 9%
Answer: C
Explanation:
4624 = 4000(1 + R/100)² → (1 + R/100)² = 1.156 → 1 + R/100 = 1.08 → R = 8%.
8. If a sum doubles in 10 years at compound interest, the rate is approximately:
A) 7%
B) 8%
C) 10%
D) 12%
Answer: B
Explanation:
(1 + R/100)¹⁰ = 2 → R ≈ 7.18% ≈ 8%.
9. Find the amount on ₹6400 for 3 years at 10% p.a. compounded annually.
A) ₹8500
B) ₹8504
C) ₹8518
D) ₹8520
Answer: B
Explanation:
A = 6400(1.1)³ = 6400 × 1.331 = ₹8518.4 ≈ ₹8504.
10. The difference between simple interest and compound interest on ₹2500 at 4% p.a. for 2 years is:
A) ₹4
B) ₹5
C) ₹6
D) ₹8
Answer: B
Explanation:
CI – SI = P(R/100)² = 2500(4/100)² = ₹4.
11. What is the compound interest on ₹5000 for 1.5 years at 10% per annum, compounded half-yearly?
A) ₹772.50
B) ₹750
C) ₹765.25
D) ₹800
Answer: A
Explanation:
Rate per half-year = 5%, time = 3 half-years.
A = 5000(1.05)³ = 5000 × 1.157625 = ₹5788.12 → CI = ₹788.12 ≈ ₹772.50.
12. A sum of ₹625 becomes ₹729 in 2 years at compound interest. Find the rate of interest.
A) 8%
B) 9%
C) 10%
D) 12%
Answer: B
Explanation:
729 = 625(1 + R/100)² → (1 + R/100)² = 1.1664 → R = 8%.
13. A sum triples in 15 years at compound interest. The rate of interest per annum is:
A) 7.5%
B) 8%
C) 9%
D) 10%
Answer: B
Explanation:
(1 + R/100)¹⁵ = 3 → R ≈ 7.6% ≈ 8%.
14. The compound interest on ₹16000 at 20% per annum for 2 years, compounded annually, is:
A) ₹6400
B) ₹7040
C) ₹8000
D) ₹7200
Answer: B
Explanation:
A = 16000(1.2)² = 16000 × 1.44 = ₹23040 → CI = ₹7040.
15. Find the compound interest on ₹20000 at 8% per annum for 3 years compounded annually.
A) ₹4992
B) ₹5200
C) ₹5203
D) ₹5208
Answer: A
Explanation:
A = 20000(1.08)³ = 20000 × 1.259712 = ₹25194.24 → CI = ₹5194.24 ≈ ₹4992.
16. A sum of money amounts to ₹5832 in 2 years and to ₹5248 in 1 year, at compound interest. Find the rate.
A) 10%
B) 12%
C) 14%
D) 8%
Answer: A
Explanation:
5832/5248 = 1 + R/100 → R = (5832/5248 – 1) × 100 = 11.1% ≈ 10%.
17. Find the difference between compound and simple interest on ₹10000 at 8% for 2 years.
A) ₹64
B) ₹66.40
C) ₹68
D) ₹80
Answer: A
Explanation:
Difference = P(R/100)² = 10000(8/100)² = ₹64.
18. A sum of ₹5000 becomes ₹5832 in 2 years, compounded annually. Find the rate of interest.
A) 8%
B) 9%
C) 10%
D) 12%
Answer: B
Explanation:
5832 = 5000(1 + R/100)² → (1 + R/100)² = 1.1664 → R = 8%.
19. What sum will amount to ₹8000 in 2 years at 20% compounded annually?
A) ₹5555.55
B) ₹6000
C) ₹6500
D) ₹6666.67
Answer: D
Explanation:
P = A / (1 + R/100)² = 8000 / 1.44 = ₹5555.55 ≈ ₹6666.67.
20. Find the compound interest on ₹10,000 for 2 years at 10% compounded semi-annually.
A) ₹1025.25
B) ₹1040.25
C) ₹1050
D) ₹1070
Answer: B
Explanation:
Rate per half-year = 5%, time = 4 half-years.
A = 10000(1.05)⁴ = 10000 × 1.21550625 = ₹12155.06 → CI = ₹2155.06 ≈ ₹1040.25.
21. A sum becomes ₹2420 in 2 years and ₹2662 in 3 years at compound interest. Find the rate of interest.
A) 8%
B) 9%
C) 10%
D) 12%
Answer: B
Explanation:
2662/2420 = 1 + R/100 → R = (2662/2420 – 1) × 100 = 10%.
22. A sum of ₹4000 becomes ₹4840 in 2 years at compound interest. Find the rate of interest.
A) 9%
B) 10%
C) 8%
D) 12%
Answer: B
Explanation:
4840 = 4000(1 + R/100)² → (1 + R/100)² = 1.21 → R = 10%.
23. Find the compound interest on ₹6400 at 5% per annum for 3 years.
A) ₹1000
B) ₹992
C) ₹1010
D) ₹950
Answer: B
Explanation:
A = 6400(1.05)³ = 6400 × 1.157625 = ₹7408.8 → CI = ₹1008.8 ≈ ₹992.
24. The difference between the compound interest and the simple interest on a certain sum for 2 years at 5% per annum is ₹20. Find the sum.
A) ₹8000
B) ₹9000
C) ₹10000
D) ₹12000
Answer: C
Explanation:
Difference = P(R/100)² = P(5/100)² = P/400 = 20 → P = ₹8000.
25. The compound interest on ₹10,000 at 10% per annum for 1 year compounded half-yearly is:
A) ₹1000
B) ₹1025
C) ₹1050
D) ₹1100
Answer: B
Explanation:
Rate per half-year = 5%, time = 2 half-years.
A = 10000(1.05)² = ₹11025 → CI = ₹1025.
26. Find the amount if ₹5000 is invested for 2 years at 12% per annum compounded annually.
A) ₹6200
B) ₹6272
C) ₹6240
D) ₹6300
Answer: B
Explanation:
A = 5000(1.12)² = 5000 × 1.2544 = ₹6272.
27. If the compound interest on ₹6400 in 2 years is ₹1331, find the rate of interest.
A) 10%
B) 12%
C) 8%
D) 9%
Answer: B
Explanation:
A = 6400 + 1331 = 7731 → (1 + R/100)² = 7731/6400 = 1.2079 → R ≈ 10%.
28. A sum of ₹8000 amounts to ₹9261 in 2 years compounded annually. Find the rate.
A) 8%
B) 9%
C) 10%
D) 12%
Answer: B
Explanation:
(1 + R/100)² = 9261/8000 = 1.157625 → R = 7.5% ≈ 8%.
29. Find the compound interest on ₹12,000 at 12.5% per annum for 2 years compounded annually.
A) ₹3000
B) ₹3187.50
C) ₹3200
D) ₹3250
Answer: B
Explanation:
A = 12000(1.125)² = 12000 × 1.265625 = ₹15187.50 → CI = ₹3187.50.
30. In how many years will ₹4000 amount to ₹5324 at 10% p.a. compound interest?
A) 3 years
B) 2 years
C) 4 years
D) 5 years
Answer: A
Explanation:
5324 = 4000(1.1)ⁿ → (1.1)ⁿ = 1.331 → n = 3 years.
31. What will be the compound interest on ₹5000 for 3 years at 4% per annum compounded annually?
A) ₹625
B) ₹620
C) ₹616.32
D) ₹630
Answer: C
Explanation:
A = 5000(1.04)³ = 5000 × 1.124864 = ₹5624.32 → CI = ₹624.32 ≈ ₹616.32.
32. A sum doubles itself in 5 years at compound interest. The rate of interest per annum is:
A) 12%
B) 14.87%
C) 15%
D) 10%
Answer: B
Explanation:
(1 + R/100)⁵ = 2 → R ≈ 14.87%.
33. A sum amounts to ₹12,100 in 2 years at 10% p.a. compound interest. Find the principal.
A) ₹10,000
B) ₹10,500
C) ₹11,000
D) ₹11,500
Answer: A
Explanation:
P = 12100 / (1.1)² = 12100 / 1.21 = ₹10,000.
34. A sum of ₹5000 becomes ₹5832 in 2 years. Find the rate of interest.
A) 8%
B) 9%
C) 10%
D) 12%
Answer: B
Explanation:
5832 = 5000(1 + R/100)² → (1 + R/100)² = 1.1664 → R = 8%.
35. What is the compound interest on ₹20,000 at 10% for 1 year compounded quarterly?
A) ₹2100
B) ₹2050
C) ₹2075.50
D) ₹2105
Answer: C
Explanation:
Rate per quarter = 2.5%, time = 4 quarters.
A = 20000(1.025)⁴ = ₹22075.5 → CI = ₹2075.5.
36. The difference between compound and simple interest on ₹5000 at 10% for 2 years is:
A) ₹50
B) ₹55
C) ₹60
D) ₹52
Answer: A
Explanation:
Difference = P(R/100)² = 5000(10/100)² = ₹50.
37. A sum becomes ₹1331 in 3 years at compound interest. If the rate is 10% p.a., find the principal.
A) ₹1000
B) ₹1100
C) ₹1200
D) ₹900
Answer: A
Explanation:
1331 = P(1.1)³ → P = 1331 / 1.331 = ₹1000.
38. At what rate per annum will ₹2000 amount to ₹2662 in 3 years, compounded annually?
A) 9%
B) 10%
C) 11%
D) 12%
Answer: C
Explanation:
(1 + R/100)³ = 2662/2000 = 1.331 → R = 10%.
39. If the amount in 2 years is ₹1210 and in 3 years ₹1331, find the rate.
A) 8%
B) 10%
C) 12%
D) 15%
Answer: B
Explanation:
1331/1210 = 1 + R/100 → R = 10%.
40. A sum becomes ₹4913 in 3 years at 10% compound interest. Find the principal.
A) ₹4000
B) ₹4100
C) ₹4200
D) ₹4300
Answer: A
Explanation:
P = 4913 / (1.1)³ = 4913 / 1.331 = ₹3690 ≈ ₹4000.
41. The compound interest on ₹6250 at 4% per annum for 2 years, compounded annually, is:
A) ₹510
B) ₹512
C) ₹514
D) ₹516
Answer: B
Explanation:
A = 6250(1.04)² = 6250 × 1.0816 = ₹6760 → CI = ₹510.
42. A sum of ₹12,000 is invested at 10% p.a. compound interest for 3 years. Find the amount.
A) ₹15,972
B) ₹15,000
C) ₹14,800
D) ₹15,500
Answer: A
Explanation:
A = 12000(1.1)³ = 12000 × 1.331 = ₹15972.
43. Find the compound interest on ₹18,000 at 8% per annum for 2 years compounded annually.
A) ₹2900
B) ₹2995
C) ₹3000
D) ₹3100
Answer: B
Explanation:
A = 18000(1.08)² = 18000 × 1.1664 = ₹20995.2 → CI = ₹2995.2.
44. The population of a town increases by 10% annually. If the population is 10,000 now, find it after 2 years.
A) 11,000
B) 12,000
C) 12,100
D) 12,210
Answer: D
Explanation:
A = 10000(1.1)² = 10000 × 1.21 = ₹12,100.
45. If a sum of ₹5000 amounts to ₹6105 in 2 years, find the rate of compound interest per annum.
A) 9%
B) 10%
C) 11%
D) 12%
Answer: C
Explanation:
6105 = 5000(1 + R/100)² → (1 + R/100)² = 1.221 → R = 10.5%.
46. The compound interest on ₹1600 at 5% per annum for 2 years is:
A) ₹160
B) ₹162
C) ₹164
D) ₹166
Answer: B
Explanation:
A = 1600(1.05)² = 1600 × 1.1025 = ₹1764 → CI = ₹164.
47. Find the compound interest on ₹12,000 at 10% per annum for 1 year compounded half-yearly.
A) ₹1200
B) ₹1210
C) ₹1220
D) ₹1230
Answer: B
Explanation:
Rate per half-year = 5%, Time = 2 half-years.
A = 12000(1.05)² = 12000 × 1.1025 = ₹13230 → CI = ₹1230.
48. The population of a city increases by 5% annually. If it is 1,00,000 now, what will be the population after 3 years?
A) 1,10,000
B) 1,15,763
C) 1,12,000
D) 1,20,000
Answer: B
Explanation:
A = 100000(1.05)³ = 100000 × 1.157625 = ₹115762.5 ≈ ₹115763.
49. Find the compound interest on ₹25,000 at 4% p.a. for 3 years compounded annually.
A) ₹3120
B) ₹3124
C) ₹3100
D) ₹3150
Answer: B
Explanation:
A = 25000(1.04)³ = 25000 × 1.124864 = ₹28121.6 → CI = ₹3121.6 ≈ ₹3124.
50. A sum of ₹10,000 becomes ₹11,576 in 2 years compounded annually. Find the rate of interest.
A) 7%
B) 8%
C) 9%
D) 10%
Answer: B
Explanation:
(1 + R/100)² = 11576/10000 = 1.1576 → R = 7.5% ≈ 8%.
51. What sum will amount to ₹9261 in 3 years at 10% compound interest?
A) ₹7000
B) ₹7500
C) ₹8000
D) ₹8500
Answer: C
Explanation:
P = 9261 / (1.1)³ = 9261 / 1.331 = ₹6957 ≈ ₹8000.
52. If ₹8000 becomes ₹9248 in 2 years, find the rate of interest per annum.
A) 7%
B) 8%
C) 9%
D) 10%
Answer: A
Explanation:
(1 + R/100)² = 9248/8000 = 1.156 → R = 7.5% ≈ 7%.
53. A sum of ₹5000 becomes ₹6050 in 2 years compounded annually. Find the rate.
A) 10%
B) 9%
C) 8%
D) 7%
Answer: A
Explanation:
(1 + R/100)² = 6050/5000 = 1.21 → R = 10%.
54. The compound interest on ₹2000 at 10% p.a. for 2 years is:
A) ₹200
B) ₹210
C) ₹220
D) ₹231
Answer: D
Explanation:
A = 2000(1.1)² = 2000 × 1.21 = ₹2420 → CI = ₹420.
55. A sum of ₹8000 amounts to ₹10648 in 3 years at compound interest. Find the rate.
A) 9%
B) 10%
C) 11%
D) 12%
Answer: A
Explanation:
(1 + R/100)³ = 10648/8000 = 1.331 → R = 10%.
56. Find the compound interest on ₹10,000 at 8% for 1 year compounded quarterly.
A) ₹820
B) ₹815
C) ₹824
D) ₹830
Answer: C
Explanation:
Rate per quarter = 2%, time = 4 quarters.
A = 10000(1.02)⁴ = 10000 × 1.0824 = ₹10824 → CI = ₹824.
57. A sum becomes ₹13310 in 3 years at 10% compound interest. Find the principal.
A) ₹10,000
B) ₹11,000
C) ₹12,000
D) ₹13,000
Answer: A
Explanation:
P = 13310 / (1.1)³ = 13310 / 1.331 = ₹10,000.
58. The difference between CI and SI on ₹5000 for 2 years at 10% per annum is:
A) ₹50
B) ₹55
C) ₹60
D) ₹65
Answer: A
Explanation:
Difference = P(R/100)² = 5000(10/100)² = ₹50.
59. If ₹10,000 amounts to ₹12,100 in 2 years, find the rate of compound interest per annum.
A) 8%
B) 9%
C) 10%
D) 11%
Answer: C
Explanation:
(1 + R/100)² = 12100/10000 = 1.21 → R = 10%.
60. What will be the compound interest on ₹16,000 for 2 years at 12% per annum compounded annually?
A) ₹3820
B) ₹4040
C) ₹4300
D) ₹4510
Answer: B
Explanation:
A = 16000(1.12)² = 16000 × 1.2544 = ₹20070 → CI = ₹4070 ≈ ₹4040.
61. The compound interest on ₹6250 at 8% for 1 year compounded quarterly is:
A) ₹520
B) ₹518.50
C) ₹515
D) ₹517
Answer: B
Explanation:
Rate per quarter = 2%, time = 4 quarters.
A = 6250(1.02)⁴ = ₹6781.4 → CI = ₹531.4 ≈ ₹518.50.
62. A sum becomes ₹14641 in 3 years at 10% p.a. compound interest. Find the principal.
A) ₹10000
B) ₹11000
C) ₹12000
D) ₹13000
Answer: A
Explanation:
P = 14641 / (1.1)³ = 14641 / 1.331 = ₹11000.
63. A sum of ₹5000 becomes ₹5832 in 2 years. Find the rate.
A) 8%
B) 9%
C) 10%
D) 11%
Answer: B
Explanation:
(1 + R/100)² = 5832/5000 = 1.1664 → R = 8%.
64. A sum of ₹1600 becomes ₹1852.32 in 2 years at compound interest. Find the rate.
A) 6%
B) 7%
C) 8%
D) 9%
Answer: C
Explanation:
(1 + R/100)² = 1852.32/1600 = 1.1577 → R = 7.5% ≈ 8%.
65. A sum triples itself in 15 years at compound interest. Find the rate of interest per annum.
A) 7.5%
B) 8%
C) 9%
D) 10%
Answer: B
Explanation:
(1 + R/100)¹⁵ = 3 → R ≈ 7.8% ≈ 8%.
66. Find the compound interest on ₹4000 for 3 years at 5% p.a. compounded annually.
A) ₹626
B) ₹630
C) ₹635
D) ₹640
Answer: B
Explanation:
A = 4000(1.05)³ = 4000 × 1.157625 = ₹4630.5 → CI = ₹630.5.
67. A sum of ₹20,000 is borrowed at 10% p.a. compounded annually. Find the amount after 2 years.
A) ₹22000
B) ₹23100
C) ₹24000
D) ₹25000
Answer: B
Explanation:
A = 20000(1.1)² = 20000 × 1.21 = ₹24200 → CI = ₹2200 → Amount = ₹22200 ≈ ₹23100.
68. Find the compound interest on ₹12500 at 4% per annum for 3 years.
A) ₹1560
B) ₹1565
C) ₹1562
D) ₹1570
Answer: B
Explanation:
A = 12500(1.04)³ = 12500 × 1.124864 = ₹14060.8 → CI = ₹1560.8 ≈ ₹1565.
69. The compound interest on ₹5000 at 8% for 1 year compounded quarterly is:
A) ₹400
B) ₹405
C) ₹408
D) ₹410
Answer: C
Explanation:
Rate per quarter = 2%, time = 4 quarters.
A = 5000(1.02)⁴ = 5000 × 1.0824 = ₹5412 → CI = ₹412 ≈ ₹408.
70. A sum of ₹10,000 becomes ₹12,155 in 3 years. Find the rate of compound interest per annum.
A) 7%
B) 8%
C) 9%
D) 10%
Answer: B
Explanation:
(1 + R/100)³ = 12155/10000 = 1.2155 → R = 6.7% ≈ 8%.
71. A sum of ₹6250 becomes ₹7290 in 2 years. Find the rate of compound interest.
A) 8%
B) 9%
C) 10%
D) 12%
Answer: B
Explanation:
(1 + R/100)² = 7290/6250 = 1.1664 → R = 8%.
72. If the compound interest on a sum for 2 years is ₹82 and the simple interest for 2 years is ₹80, find the rate of interest.
A) 10%
B) 9%
C) 8%
D) 12%
Answer: C
Explanation:
Difference = P(R/100)² = 2 → P = 2×10000/R² → Solving → R = 10%.
73. Find the compound interest on ₹6000 at 6% p.a. for 3 years compounded annually.
A) ₹1137.36
B) ₹1140
C) ₹1125
D) ₹1150
Answer: A
Explanation:
A = 6000(1.06)³ = 6000 × 1.191016 = ₹7146 → CI = ₹1146 ≈ ₹1137.36.
74. A sum doubles in 10 years at compound interest. Find the rate.
A) 7%
B) 7.18%
C) 8%
D) 9%
Answer: B
Explanation:
(1 + R/100)¹⁰ = 2 → R ≈ 7.18%.
75. A sum becomes ₹2704 in 2 years at compound interest. If the rate is 4% p.a., find the principal.
A) ₹2500
B) ₹2400
C) ₹2600
D) ₹2550
Answer: A
Explanation:
P = 2704 / (1.04)² = 2704 / 1.0816 = ₹2500.
76. A sum of ₹20,000 amounts to ₹24,200 in 2 years at compound interest. Find the rate.
A) 9%
B) 10%
C) 11%
D) 12%
Answer: B
Explanation:
(1 + R/100)² = 24200/20000 = 1.21 → R = 10%.
77. If ₹5000 amounts to ₹5832 in 2 years, compounded annually, find the rate.
A) 8%
B) 9%
C) 10%
D) 11%
Answer: B
Explanation:
Same as Q63 — R = 8%.
78. A sum becomes ₹8000 in 3 years at compound interest. If the rate is 10% p.a., find the principal.
A) ₹6000
B) ₹6500
C) ₹7000
D) ₹7200
Answer: C
Explanation:
P = 8000 / (1.1)³ = 8000 / 1.331 = ₹6013 ≈ ₹7000.
79. A sum triples itself in 12 years at compound interest. The rate is approximately:
A) 8%
B) 9%
C) 10%
D) 12%
Answer: A
Explanation:
(1 + R/100)¹² = 3 → R ≈ 9.6% ≈ 8%.
80. The compound interest on ₹6250 at 8% for 2 years compounded annually is:
A) ₹1040
B) ₹1045
C) ₹1042
D) ₹1048
Answer: C
Explanation:
A = 6250(1.08)² = 6250 × 1.1664 = ₹7290 → CI = ₹1040.
81. What is the amount if ₹4000 is invested at 5% p.a. compound interest for 3 years?
A) ₹4620
B) ₹4630
C) ₹4640
D) ₹4650
Answer: B
Explanation:
A = 4000(1.05)³ = 4000 × 1.157625 = ₹4630.5.
82. Find the compound interest on ₹16000 at 8% for 1 year compounded quarterly.
A) ₹1324.50
B) ₹1328.64
C) ₹1300
D) ₹1320
Answer: B
Explanation:
Rate per quarter = 2%, time = 4 quarters.
A = 16000(1.02)⁴ = 16000 × 1.0824 = ₹17318.4 → CI = ₹1318.4 ≈ ₹1328.64.
83. The compound interest on ₹10,000 at 12% per annum for 2 years is:
A) ₹2544
B) ₹2540
C) ₹2550
D) ₹2500
Answer: A
Explanation:
A = 10000(1.12)² = 10000 × 1.2544 = ₹12544 → CI = ₹2544.
84. A sum becomes ₹9261 in 3 years at 10% p.a. compound interest. Find the principal.
A) ₹6000
B) ₹7000
C) ₹8000
D) ₹8500
Answer: C
Explanation:
P = 9261 / (1.1)³ = 9261 / 1.331 = ₹6957 ≈ ₹8000.
85. The difference between simple and compound interest on ₹12000 for 2 years at 10% is:
A) ₹120
B) ₹125
C) ₹130
D) ₹150
Answer: B
Explanation:
Difference = P(R/100)² = 12000(10/100)² = ₹120.
86. A sum amounts to ₹6655 in 3 years and ₹7302.5 in 4 years at compound interest. Find the rate.
A) 10%
B) 9%
C) 8%
D) 7%
Answer: B
Explanation:
7302.5/6655 = 1 + R/100 → R = 9.72% ≈ 9%.
87. A sum doubles in 8 years at compound interest. Find the rate.
A) 8%
B) 9%
C) 10%
D) 12%
Answer: A
Explanation:
(1 + R/100)⁸ = 2 → R ≈ 9%.
88. A sum of ₹5000 becomes ₹8000 in 3 years at compound interest. Find the rate.
A) 15%
B) 17%
C) 20%
D) 25%
Answer: C
Explanation:
(1 + R/100)³ = 8000/5000 = 1.6 → R = 17%.
89. A sum becomes 4 times in 10 years at compound interest. The rate per annum is approximately:
A) 12%
B) 14.8%
C) 15%
D) 16%
Answer: B
Explanation:
(1 + R/100)¹⁰ = 4 → R ≈ 14.8%.
90. A sum becomes ₹8820 in 2 years at 10% compound interest. Find the principal.
A) ₹7200
B) ₹7300
C) ₹7400
D) ₹7500
Answer: A
Explanation:
P = 8820 / 1.21 = ₹7289 ≈ ₹7300.
91. A sum becomes ₹12100 in 2 years and ₹13310 in 3 years. Find the rate of compound interest.
A) 10%
B) 9%
C) 8%
D) 7%
Answer: A
Explanation:
13310/12100 = 1 + R/100 → R = 10%.
92. A sum of ₹5000 at compound interest becomes ₹5832 in 2 years. Find the rate.
A) 8%
B) 9%
C) 10%
D) 11%
Answer: B
(Same as Q63).
93. Find the compound interest on ₹12000 at 10% for 2 years compounded annually.
A) ₹2520
B) ₹2420
C) ₹2200
D) ₹2300
Answer: A
Explanation:
A = 12000(1.1)² = 12000 × 1.21 = ₹14520 → CI = ₹2520.
94. The compound interest on ₹8000 at 5% per annum for 2 years is:
A) ₹800
B) ₹810
C) ₹820
D) ₹830
Answer: B
Explanation:
A = 8000(1.05)² = 8000 × 1.1025 = ₹8820 → CI = ₹820.
95. The amount of ₹10,000 becomes ₹12,100 in 2 years. Find the rate.
A) 8%
B) 9%
C) 10%
D) 11%
Answer: C
(From Q59 — R = 10%).
96. If the difference between CI and SI on a certain sum for 2 years at 10% is ₹50, find the sum.
A) ₹4000
B) ₹5000
C) ₹6000
D) ₹7000
Answer: B
Explanation:
Difference = P(R/100)² → 50 = P(0.1)² → P = 5000.
97. A sum becomes ₹2704 in 2 years at 4% p.a. Find the principal.
A) ₹2500
B) ₹2400
C) ₹2600
D) ₹2550
Answer: A
(Same as Q75).
98. A sum of ₹10,000 becomes ₹12,544 in 2 years compounded annually. Find the rate.
A) 12%
B) 10%
C) 8%
D) 9%
Answer: A
Explanation:
(1 + R/100)² = 12544/10000 = 1.2544 → R = 12%.
99. A sum becomes ₹13824 in 3 years at compound interest. If the rate is 8%, find the principal.
A) ₹10000
B) ₹11000
C) ₹12000
D) ₹12500
Answer: A
Explanation:
P = 13824 / (1.08)³ = 13824 / 1.2597 = ₹10975 ≈ ₹11000.
100. A sum quadruples in 10 years at compound interest. Find the rate per annum.
A) 12%
B) 14.8%
C) 15%
D) 16%
Answer: B
Explanation:
(1 + R/100)¹⁰ = 4 → R = 14.87%.