1. What will be the simple interest on ₹5000 at 12% per annum for 2 years?
a) ₹1000
b) ₹1100
c) ₹1200
d) ₹1250
Answer: c) ₹1200
Explanation: SI = (P × R × T) / 100 = (5000 × 12 × 2)/100 = 1200.
2. A sum of ₹800 amounts to ₹920 in 3 years at simple interest. The rate of interest is:
a) 4%
b) 5%
c) 6%
d) 7%
Answer: b) 5%
Explanation: SI = 920 – 800 = 120. → R = (100×120)/(800×3) = 5%.
3. At what rate of interest will ₹4000 amount to ₹4600 in 3 years at simple interest?
a) 4%
b) 5%
c) 6%
d) 7%
Answer: b) 5%
Explanation: SI = 600. → R = (100×600)/(4000×3) = 5%.
4. The SI on a sum of money is 1/9 of the principal. The rate × time is:
a) 5%
b) 9%
c) 11.11%
d) 100/9 %
Answer: d) 100/9 %
Explanation: SI = (P×R×T)/100 = P/9 → RT = 100/9.
5. A sum doubles itself in 10 years at SI. The rate of interest is:
a) 5%
b) 7%
c) 8%
d) 10%
Answer: d) 10%
Explanation: SI = P → (P×R×10)/100 = P → R = 10%.
6. At 12% per annum, how many years will a sum of money double itself at SI?
a) 6 years
b) 7 years
c) 8.33 years
d) 9 years
Answer: c) 8.33 years
Explanation: SI = P → (P×12×T)/100 = P → T = 100/12 = 8.33 years.
7. What will be the SI on ₹2500 for 4 years at 8% per annum?
a) ₹600
b) ₹700
c) ₹750
d) ₹800
Answer: d) ₹800
Explanation: SI = (2500×8×4)/100 = 800.
8. A sum of ₹500 amounts to ₹650 in 4 years at SI. The rate % is:
a) 5%
b) 6%
c) 7.5%
d) 8%
Answer: c) 7.5%
Explanation: SI = 150 → R = (100×150)/(500×4) = 7.5%.
9. The SI on a sum for 5 years is one-fourth of the principal. The rate % is:
a) 4%
b) 5%
c) 6%
d) 8%
Answer: b) 5%
Explanation: (P×R×5)/100 = P/4 → R = 5%.
10. Find the SI on ₹4000 at 5% per annum for 3 years.
a) ₹500
b) ₹550
c) ₹600
d) ₹700
Answer: c) ₹600
Explanation: (4000×5×3)/100 = 600.
11. At what rate % will a sum of ₹2400 yield SI of ₹864 in 6 years?
a) 5%
b) 6%
c) 7%
d) 8%
Answer: d) 6%
Explanation: R = (100×864)/(2400×6) = 6%.
12. A sum trebles itself in 20 years at SI. The rate of interest is:
a) 5%
b) 10%
c) 12%
d) 15%
Answer: a) 10%
Explanation: SI = 2P → (P×R×20)/100 = 2P → R = 10%.
13. If the SI on ₹500 for 3 years is ₹180, what is the rate of interest?
a) 10%
b) 11%
c) 12%
d) 13%
Answer: c) 12%
Explanation: (500×R×3)/100 = 180 → R = 12%.
14. If SI on ₹1000 for 3 years at R% is ₹360, then R is:
a) 10%
b) 11%
c) 12%
d) 13%
Answer: c) 12%
Explanation: (1000×R×3)/100 = 360 → R = 12%.
15. In how many years will ₹2000 double itself at 10% SI?
a) 5 years
b) 8 years
c) 10 years
d) 12 years
Answer: c) 10 years
Explanation: SI = P → (2000×10×T)/100 = 2000 → T = 10.
16. A sum of ₹6000 amounts to ₹9000 in 5 years at SI. The rate is:
a) 8%
b) 9%
c) 10%
d) 12%
Answer: c) 10%
Explanation: SI = 3000 → R = (100×3000)/(6000×5) = 10%.
17. What is the CI on ₹1000 at 10% p.a. for 2 years (compounded annually)?
a) ₹200
b) ₹210
c) ₹220
d) ₹230
Answer: b) ₹210
Explanation: A = 1000(1+10/100)² = 1210 → CI = 210.
18. The CI on a sum of ₹8000 at 10% for 2 years is:
a) ₹1600
b) ₹1650
c) ₹1680
d) ₹1700
Answer: b) ₹1680
Explanation: A = 8000(1.1)² = 9680 → CI = 1680.
19. If ₹10000 becomes ₹12100 in 2 years at CI, the rate is:
a) 8%
b) 9%
c) 10%
d) 11%
Answer: c) 10%
Explanation: A/P = 12100/10000 = 1.21 → (1+R/100)² = 1.21 → R = 10%.
20. The CI on ₹5000 for 2 years at 10% compounded annually is:
a) ₹1000
b) ₹1050
c) ₹1100
d) ₹1150
Answer: b) ₹1050
Explanation: A = 5000×(1.1)² = 6050 → CI = 1050.
21. The difference between CI and SI on ₹5000 at 10% for 2 years is:
a) ₹40
b) ₹45
c) ₹50
d) ₹55
Answer: c) ₹50
Explanation: SI = 1000, CI = 1050 → Difference = 50.
22. At what rate % will a sum of money double in 8 years at CI (compounded annually)?
a) 8.66%
b) 9%
c) 9.5%
d) 10%
Answer: b) 9%
Explanation: (1+R/100)⁸ = 2 → R ≈ 9%.
23. A sum becomes ₹1331 in 3 years at CI. If the principal is ₹1000, the rate is:
a) 8%
b) 9%
c) 10%
d) 11%
Answer: d) 10%
Explanation: (1+R/100)³ = 1331/1000 = 1.331 → R = 10%.
24. The CI on ₹2000 at 5% p.a. for 3 years is:
a) ₹300
b) ₹315.25
c) ₹320
d) ₹325.25
Answer: b) ₹315.25
Explanation: A = 2000(1.05)³ = 2315.25 → CI = 315.25.
25. The difference between CI and SI on ₹4000 at 5% for 2 years is:
a) ₹5
b) ₹8
c) ₹10
d) ₹12
Answer: c) ₹10
Explanation: SI = 400, CI = 410 → Difference = 10.
26. What will be the CI on ₹10,000 at 20% per annum for 2 years?
a) ₹4000
b) ₹4200
c) ₹4400
d) ₹4600
Answer: b) ₹4200
Explanation: A = 10000(1.2)² = 14400 → CI = 4400. Wait correction: 14400 – 10000 = 4400. Correct Answer = c) ₹4400.
27. Find the difference between CI and SI on ₹5000 at 8% per annum for 2 years.
a) ₹16
b) ₹20
c) ₹25
d) ₹30
Answer: c) ₹20
Explanation: SI = 800. CI = 5000(1.08)² – 5000 = 832 – 800 = 20 difference.
28. The CI on a sum of ₹12,000 at 10% p.a. for 2 years is:
a) ₹2400
b) ₹2500
c) ₹2520
d) ₹2600
Answer: c) ₹2520
Explanation: A = 12000(1.1)² = 14520 → CI = 2520.
29. A sum becomes ₹9261 in 3 years at CI. If the rate is 10%, the principal is:
a) ₹6800
b) ₹7000
c) ₹7500
d) ₹8000
Answer: d) ₹7000
Explanation: P = A/(1.1)³ = 9261/1.331 = 6969 ≈ 7000.
30. The CI on ₹4000 at 5% for 3 years is:
a) ₹600
b) ₹610
c) ₹620
d) ₹630
Answer: b) ₹630.50 (≈ ₹630)
Explanation: A = 4000(1.05)³ = 4630.50 → CI = 630.50. Closest option = d) ₹630.
31. The SI on ₹6000 for 5 years is ₹2400. The rate of interest is:
a) 7%
b) 8%
c) 9%
d) 10%
Answer: b) 8%
Explanation: (6000×R×5)/100 = 2400 → R = 8%.
32. ₹800 becomes ₹920 in 3 years at SI. What will be the amount after 6 years?
a) ₹1040
b) ₹1080
c) ₹1100
d) ₹1120
Answer: d) ₹1120
Explanation: SI for 3 years = 120 → SI for 6 years = 240 → Amount = 800+240=1120.
33. At what rate % will a sum of ₹5000 earn ₹1000 SI in 4 years?
a) 4%
b) 5%
c) 6%
d) 7%
Answer: b) 5%
Explanation: (5000×R×4)/100 = 1000 → R = 5%.
34. If a sum becomes ₹7920 in 2 years at CI and the rate is 10%, the principal is:
a) ₹6400
b) ₹6500
c) ₹6600
d) ₹7200
Answer: d) ₹7200
Explanation: P = A/(1.1)² = 7920/1.21 = 6545. (Wait miscalc) Correct: 7920/(1.21) = 6545 ≈ c) ₹6600.
35. The SI on ₹1500 at 12% per annum for 4 years is:
a) ₹640
b) ₹700
c) ₹720
d) ₹740
Answer: c) ₹720
Explanation: (1500×12×4)/100 = 720.
36. A sum becomes ₹16900 in 2 years at 30% CI. The principal is:
a) ₹10000
b) ₹11000
c) ₹12000
d) ₹12500
Answer: a) ₹10000
Explanation: P = 16900/(1.3)² = 10000.
37. The CI on ₹4000 at 5% p.a. for 2 years compounded annually is:
a) ₹400
b) ₹410
c) ₹420
d) ₹430
Answer: b) ₹410
Explanation: A = 4000(1.05)² = 4410 → CI = 410.
38. A sum of ₹5000 becomes ₹5832 in 2 years at CI. The rate of interest is:
a) 7%
b) 8%
c) 9%
d) 10%
Answer: c) 8%
Explanation: (1+R/100)² = 5832/5000 = 1.1664 → R = 8%.
39. At what rate % will a sum of money double itself in 10 years at SI?
a) 8%
b) 9%
c) 10%
d) 12%
Answer: c) 10%
Explanation: SI = P → (P×R×10)/100 = P → R=10%.
40. The SI on a sum for 4 years at 12% is ₹4800. The principal is:
a) ₹9000
b) ₹10000
c) ₹11000
d) ₹12000
Answer: b) ₹10000
Explanation: (P×12×4)/100 = 4800 → P = 10000.
41. If ₹1200 becomes ₹1920 in 4 years at SI, the rate is:
a) 10%
b) 12%
c) 15%
d) 18%
Answer: c) 15%
Explanation: SI = 720 → (1200×R×4)/100 = 720 → R=15%.
42. The CI on ₹10,000 at 10% compounded half-yearly for 1 year is:
a) ₹1000
b) ₹1010
c) ₹1025
d) ₹1050
Answer: c) ₹1025
Explanation: A = 10000(1+0.05)² = 11025 → CI=1025.
43. The CI on ₹20,000 for 1 year at 10% compounded quarterly is:
a) ₹2000
b) ₹2050
c) ₹2075.50
d) ₹2100
Answer: c) ₹2075.50
Explanation: A = 20000(1+0.025)⁴ = 22075.5 → CI = 2075.5.
44. The difference between SI and CI on ₹4000 at 10% for 2 years is:
a) ₹20
b) ₹30
c) ₹40
d) ₹50
Answer: c) ₹40
Explanation: SI=800, CI=840 → Difference=40.
45. What will be the CI on ₹12,000 at 12.5% p.a. for 2 years?
a) ₹3000
b) ₹3125
c) ₹3150
d) ₹3200
Answer: b) ₹3125
Explanation: A = 12000(1.125)² = 15125 → CI=3125.
46. The SI on ₹8000 at 12% for 3 years is:
a) ₹2500
b) ₹2600
c) ₹2800
d) ₹2900
Answer: c) ₹2880
Explanation: (8000×12×3)/100 = 2880.
47. A sum of ₹5000 amounts to ₹6050 in 2 years at CI. The rate % is:
a) 10%
b) 12%
c) 14%
d) 15%
Answer: a) 10%
Explanation: A/P=6050/5000=1.21 → (1+R/100)²=1.21 → R=10%.
48. The CI on ₹6000 at 20% for 2 years compounded annually is:
a) ₹2400
b) ₹2500
c) ₹2600
d) ₹2640
Answer: d) ₹2640
Explanation: A=6000(1.2)²=8640 → CI=2640.
49. The SI on ₹5000 at 9% for 4 years is:
a) ₹1600
b) ₹1700
c) ₹1800
d) ₹1900
Answer: c) ₹1800
Explanation: (5000×9×4)/100=1800.
50. The CI on ₹8000 at 5% for 3 years is:
a) ₹1200
b) ₹1250
c) ₹1261
d) ₹1280
Answer: c) ₹1261
Explanation: A=8000(1.05)³=9261 → CI=1261.
51. A sum of ₹4000 amounts to ₹4640 in 2 years at simple interest. What is the rate of interest per annum?
a) 6%
b) 7%
c) 8%
d) 10%
Answer: c) 8%
Explanation: SI = 4640 – 4000 = 640. Rate = (SI × 100) / (P × T) = (640 × 100) / (4000 × 2) = 8%.
52. A sum doubles in 5 years at simple interest. What is the rate of interest per annum?
a) 10%
b) 15%
c) 20%
d) 25%
Answer: c) 20%
Explanation: For doubling, SI = P. Time = 5 years. Rate = (SI × 100) / (P × T) = (P × 100) / (P × 5) = 20%.
53. A sum of ₹6000 amounts to ₹7200 in 3 years at simple interest. Find the rate of interest.
a) 5%
b) 6%
c) 7%
d) 8%
Answer: d) 8%
Explanation: SI = 7200 – 6000 = 1200. Rate = (1200 × 100) / (6000 × 3) = 8%.
54. A person invests ₹5000 at 12% simple interest for 4 years. Find the interest earned.
a) ₹2200
b) ₹2300
c) ₹2400
d) ₹2500
Answer: c) ₹2400
Explanation: SI = (P × R × T) / 100 = (5000 × 12 × 4)/100 = 2400.
55. A sum becomes ₹7200 in 2 years at simple interest at 12% per annum. Find the principal.
a) ₹6000
b) ₹6200
c) ₹6400
d) ₹6500
Answer: a) ₹6000
Explanation: A = P(1 + RT/100) = P(1 + 24/100) = 1.24P.
So, 7200 = 1.24P ⇒ P = 6000.
56. The difference between simple interest and compound interest on ₹5000 at 10% per annum for 2 years is:
a) ₹40
b) ₹50
c) ₹60
d) ₹70
Answer: b) ₹50
Explanation: SI = (5000 × 10 × 2)/100 = 1000.
CI = 5000(1.1² – 1) = 5000(1.21 – 1) = 1050. Difference = 50.
57. The simple interest on a sum at 5% per annum for 3 years is ₹600. Find the principal.
a) ₹3500
b) ₹3600
c) ₹3800
d) ₹4000
Answer: d) ₹4000
Explanation: SI = (P × R × T)/100 ⇒ 600 = (P × 5 × 3)/100 ⇒ P = 4000.
58. The compound interest on ₹2000 at 10% per annum for 2 years, compounded annually, is:
a) ₹400
b) ₹420
c) ₹440
d) ₹450
Answer: b) ₹420
Explanation: CI = P[(1 + R/100)^T – 1] = 2000[(1.1²) – 1] = 2000(1.21 – 1) = 420.
59. A sum of ₹10,000 becomes ₹12,100 in 2 years at compound interest. Find the rate of interest.
a) 5%
b) 10%
c) 15%
d) 20%
Answer: b) 10%
Explanation: A = P(1 + R/100)² ⇒ 12100 = 10000(1 + R/100)² ⇒ (1 + R/100)² = 1.21 ⇒ R = 10%.
60. A sum of ₹8000 amounts to ₹9680 in 3 years at simple interest. Find the rate of interest.
a) 6%
b) 7%
c) 8%
d) 9%
Answer: c) 7%
Explanation: SI = 9680 – 8000 = 1680.
Rate = (1680 × 100)/(8000 × 3) = 7%.
61. A sum of ₹5000 yields ₹600 as simple interest in 2 years. Find the rate of interest.
a) 5%
b) 6%
c) 7%
d) 8%
Answer: b) 6%
Explanation: Rate = (SI × 100)/(P × T) = (600 × 100)/(5000 × 2) = 6%.
62. A sum of ₹12,000 amounts to ₹15,000 in 4 years at simple interest. Find the rate of interest.
a) 5%
b) 6.25%
c) 7%
d) 7.5%
Answer: b) 6.25%
Explanation: SI = 15,000 – 12,000 = 3000. Rate = (3000 × 100)/(12000 × 4) = 6.25%.
63. A sum triples itself in 16 years at simple interest. Find the rate of interest.
a) 10%
b) 12.5%
c) 15%
d) 18%
Answer: b) 12.5%
Explanation: For tripling, SI = 2P. Rate = (2P × 100)/(P × 16) = 12.5%.
64. The difference between SI and CI on a sum of ₹10,000 at 10% per annum for 3 years is:
a) ₹30
b) ₹50
c) ₹100
d) ₹150
Answer: d) ₹150
Explanation: SI = (10000 × 10 × 3)/100 = 3000.
CI = 10000(1.1³ – 1) = 3310. Difference = 310 – 3000 = 310? Wait correction: 10000 × (1.331 – 1) = 3310 ⇒ Difference = 310.
Correct Answer = ₹310 (not in given options, but actual value).
65. A sum of money at compound interest becomes ₹1210 in 2 years and ₹1331 in 3 years. Find the rate.
a) 8%
b) 9%
c) 10%
d) 11%
Answer: c) 10%
Explanation: A3/A2 = 1331/1210 = 1.1 ⇒ R = 10%.
66. A sum of ₹20,000 is invested at 5% per annum compounded annually. Find the compound interest for 2 years.
a) ₹2050
b) ₹2100
c) ₹2050
d) ₹2200
Answer: a) ₹2050
Explanation: CI = 20000[(1.05²) – 1] = 20000(1.1025 – 1) = 2050.
67. If ₹5000 amounts to ₹6050 in 2 years at compound interest, find the rate.
a) 9%
b) 10%
c) 11%
d) 12%
Answer: c) 10%
Explanation: A = P(1 + R/100)² ⇒ 6050/5000 = (1 + R/100)² ⇒ 1.21 ⇒ R = 10%.
68. A sum amounts to ₹10,800 in 3 years at 10% simple interest. Find the principal.
a) ₹8000
b) ₹8200
c) ₹8400
d) ₹8800
Answer: a) ₹8000
Explanation: A = P(1 + RT/100) = P(1 + 30/100) = 1.3P. ⇒ P = 10800/1.3 = 8000.
69. A sum doubles in 8 years at compound interest. Find the rate per annum (approx).
a) 8.5%
b) 9%
c) 9.05%
d) 9.25%
Answer: b) 9%
Explanation: 2 = (1 + R/100)^8. Taking 8th root, 1 + R/100 ≈ 2^(1/8) ≈ 1.09 ⇒ R ≈ 9%.
70. A sum of ₹12,000 amounts to ₹15,552 in 3 years at compound interest. Find the rate of interest.
a) 8%
b) 9%
c) 10%
d) 12%
Answer: a) 9%
Explanation: A/P = (1 + R/100)^3 ⇒ 15552/12000 = 1.296.
Cube root of 1.296 = 1.09 ⇒ R = 9%.
71. A person invests ₹5000 at 8% compound interest for 2 years. Find the amount.
a) ₹5830
b) ₹5832
c) ₹5840
d) ₹5850
Answer: b) ₹5832
Explanation: A = 5000(1.08²) = 5000 × 1.1664 = 5832.
72. A sum of ₹10,000 at 8% simple interest for 5 years yields:
a) ₹4000
b) ₹4200
c) ₹4400
d) ₹4800
Answer: a) ₹4000
Explanation: SI = (10000 × 8 × 5)/100 = 4000.
73. A sum invested at 5% compound interest amounts to ₹441 in 2 years. Find the principal.
a) ₹400
b) ₹420
c) ₹430
d) ₹440
Answer: a) ₹400
Explanation: A = P(1.05²) = P(1.1025). ⇒ P = 441/1.1025 = 400.
74. The compound interest on ₹1600 at 20% for 2 years is:
a) ₹640
b) ₹672
c) ₹700
d) ₹720
Answer: b) ₹672
Explanation: A = 1600(1.2²) = 1600 × 1.44 = 2304. CI = 2304 – 1600 = 704? Wait correction: 1600 × 0.44 = 704. Correct = ₹704 (not in given options).
75. A sum becomes 4 times in 12 years at compound interest. Find the rate per annum.
a) 10%
b) 12%
c) 12.25%
d) 12.5%
Answer: d) 12.25%
Explanation: 4 = (1 + R/100)^12. ⇒ (1 + R/100) = 4^(1/12) ≈ 1.1225 ⇒ R ≈ 12.25%.
76. A sum of ₹6400 amounts to ₹7744 in 2 years at compound interest. Find the rate of interest.
a) 8%
b) 10%
c) 12%
d) 14%
Answer: a) 10%
Explanation: A/P = (1 + R/100)² ⇒ 7744/6400 = 1.21 ⇒ 1 + R/100 = 1.1 ⇒ R = 10%.
77. The simple interest on ₹8000 at 12% per annum for 9 months is:
a) ₹720
b) ₹800
c) ₹850
d) ₹900
Answer: a) ₹720
Explanation: SI = (P × R × T)/100 = (8000 × 12 × 9/12)/100 = 720.
78. A sum becomes ₹4900 in 2 years and ₹5390 in 3 years at simple interest. Find the principal.
a) ₹4200
b) ₹4300
c) ₹4400
d) ₹4500
Answer: a) ₹4200
Explanation: Difference of amounts = 5390 – 4900 = 490 = SI for 1 year. So, SI for 2 years = 980.
Principal = 4900 – 980 = 4200.
79. A sum invested at 5% compound interest amounts to ₹11,025 in 2 years. Find the principal.
a) ₹10,000
b) ₹10,200
c) ₹10,300
d) ₹10,500
Answer: a) ₹10,000
Explanation: A = P(1.05²) = P(1.1025). ⇒ P = 11025/1.1025 = 10000.
80. A sum becomes ₹1331 in 3 years at compound interest. If the rate is 10%, find the principal.
a) ₹900
b) ₹1000
c) ₹1100
d) ₹1200
Answer: b) ₹1000
Explanation: A = P(1.1³) = P(1.331). ⇒ P = 1331/1.331 = 1000.
81. At what rate per annum will a sum of ₹2500 yield ₹200 as simple interest in 2 years?
a) 3%
b) 4%
c) 5%
d) 6%
Answer: c) 4%
Explanation: Rate = (SI × 100)/(P × T) = (200 × 100)/(2500 × 2) = 4%.
82. The difference between CI and SI on ₹5000 at 8% for 2 years is:
a) ₹16
b) ₹20
c) ₹24
d) ₹32
Answer: c) ₹32
Explanation: SI = (5000 × 8 × 2)/100 = 800.
CI = 5000(1.08² – 1) = 5000 × 0.1664 = 832. Difference = 32.
83. The compound interest on ₹4000 at 10% per annum for 3 years is:
a) ₹1200
b) ₹1210
c) ₹1331
d) ₹1330
Answer: c) ₹1331
Explanation: A = 4000(1.1³) = 4000 × 1.331 = 5324.
CI = 5324 – 4000 = 1331.
84. A sum of ₹6000 amounts to ₹6600 in 2 years at simple interest. Find the rate of interest.
a) 4%
b) 5%
c) 6%
d) 8%
Answer: b) 5%
Explanation: SI = 6600 – 6000 = 600. Rate = (600 × 100)/(6000 × 2) = 5%.
85. The CI on ₹12,000 for 2 years at 5% per annum compounded annually is:
a) ₹1200
b) ₹1225
c) ₹1230
d) ₹1250
Answer: b) ₹1225
Explanation: A = 12000(1.05²) = 12000 × 1.1025 = 13,230. CI = 1230. Wait correction: 12000 × 0.1025 = 1230 (not in options). Correct = ₹1230.
86. A sum doubles in 10 years at simple interest. Find the rate.
a) 8%
b) 9%
c) 10%
d) 12%
Answer: c) 10%
Explanation: For doubling, SI = P. Rate = (100/10) = 10%.
87. A sum invested at 20% CI per annum amounts to ₹1728 in 3 years. Find the principal.
a) ₹1000
b) ₹1100
c) ₹1200
d) ₹1250
Answer: a) ₹1000
Explanation: A = P(1.2³) = P × 1.728. ⇒ P = 1728/1.728 = 1000.
88. A sum amounts to ₹2028 in 3 years at 4% CI per annum. Find the principal.
a) ₹1800
b) ₹1850
c) ₹1900
d) ₹2000
Answer: d) ₹1800
Explanation: A = P(1.04³) = P × 1.124864. ⇒ P = 2028/1.124864 ≈ 1800.
89. The CI on ₹10,000 at 10% for 4 years is:
a) ₹4641
b) ₹4640
c) ₹5000
d) ₹5200
Answer: a) ₹4641
Explanation: A = 10000(1.1⁴) = 10000 × 1.4641 = 14641.
CI = 4641.
90. If ₹6400 amounts to ₹7744 in 2 years at CI, find the rate of interest.
a) 8%
b) 9%
c) 10%
d) 12%
Answer: c) 10%
Explanation: Already solved above: A/P = 1.21 ⇒ Rate = 10%.
91. At what rate will ₹1600 yield ₹252 as SI in 3 years?
a) 4%
b) 5%
c) 5.25%
d) 5.5%
Answer: b) 5.25%
Explanation: Rate = (252 × 100)/(1600 × 3) = 5.25%.
92. The CI on ₹625 at 4% compounded annually for 2 years is:
a) ₹50
b) ₹51
c) ₹52
d) ₹53
Answer: b) ₹51
Explanation: A = 625(1.04²) = 625 × 1.0816 = 676.
CI = 676 – 625 = 51.
93. A sum of ₹5000 amounts to ₹6050 in 2 years at CI. Find the rate.
a) 9%
b) 10%
c) 11%
d) 12%
Answer: b) 10%
Explanation: A/P = 6050/5000 = 1.21 = (1 + R/100)² ⇒ R = 10%.
94. A sum doubles itself in 6 years at CI. Find the rate.
a) 10%
b) 12%
c) 12.25%
d) 12.5%
Answer: d) 12.25%
Explanation: 2 = (1 + R/100)^6 ⇒ (1 + R/100) = 2^(1/6) ≈ 1.1225 ⇒ R ≈ 12.25%.
95. The SI on a sum of ₹4000 at 7.5% per annum for 4 years is:
a) ₹1100
b) ₹1200
c) ₹1300
d) ₹1400
Answer: b) ₹1200
Explanation: SI = (4000 × 7.5 × 4)/100 = 1200.
96. A sum amounts to ₹9261 in 3 years at 10% CI. Find the principal.
a) ₹6800
b) ₹6900
c) ₹7000
d) ₹7500
Answer: c) ₹7000
Explanation: A = P(1.1³) = P × 1.331 ⇒ P = 9261/1.331 = 7000.
97. At what rate will ₹2500 yield ₹500 as SI in 4 years?
a) 4%
b) 5%
c) 6%
d) 7%
Answer: b) 5%
Explanation: Rate = (500 × 100)/(2500 × 4) = 5%.
98. A sum invested at 5% CI per annum amounts to ₹2205 in 2 years. Find the principal.
a) ₹2000
b) ₹2050
c) ₹2100
d) ₹2150
Answer: a) ₹2000
Explanation: A = P(1.05²) = P × 1.1025 ⇒ P = 2205/1.1025 = 2000.
99. The CI on ₹20,000 for 2 years at 8% per annum is:
a) ₹3200
b) ₹3328
c) ₹3400
d) ₹3500
Answer: b) ₹3328
Explanation: A = 20000(1.08²) = 20000 × 1.1664 = 23,328.
CI = 3328.
100. A sum triples in 15 years at CI. Find the rate per annum.
a) 8%
b) 7.5%
c) 7.9%
d) 8.25%
Answer: c) 7.9%
Explanation: 3 = (1 + R/100)¹⁵ ⇒ (1 + R/100) = 3^(1/15) ≈ 1.079 ⇒ R ≈ 7.9%.