{"id":12512,"date":"2025-09-18T05:26:01","date_gmt":"2025-09-18T04:26:01","guid":{"rendered":"https:\/\/mcqsadda.com\/?p=12512"},"modified":"2025-11-05T07:31:57","modified_gmt":"2025-11-05T07:31:57","slug":"the-human-eye-and-defects-top-100-mcqs-with-answer-and-explanation","status":"publish","type":"post","link":"https:\/\/mcqsadda.com\/index.php\/2025\/09\/18\/the-human-eye-and-defects-top-100-mcqs-with-answer-and-explanation\/","title":{"rendered":"The Human eye and defects Top 100 MCQs With Answer and Explanation"},"content":{"rendered":"\n

1.Which part of the human eye is responsible for controlling the amount of light entering the eye?<\/mark><\/strong>
A) Pupil
B) Iris
C) Cornea
D) Lens
Answer:<\/strong> B) Iris
Explanation:<\/strong> Iris is the colored muscular diaphragm that changes the size of the pupil depending on light intensity. The pupil is the opening; iris controls its size.<\/p>\n\n\n\n

2.What is the minimum distance at which a normal healthy eye can clearly see an object without strain?<\/mark><\/strong>
A) 10 cm
B) 25 cm
C) 50 cm
D) 100 cm
Answer:<\/strong> B) 25 cm
Explanation:<\/strong> The near point (least distance of distinct vision) of a normal young adult is about 25 cm.<\/p>\n\n\n\n

3.A person can see nearby objects clearly but distant objects appear blurred. What is the defect?<\/mark><\/strong>
A) Hypermetropia (Long-sightedness)
B) Myopia (Short-sightedness)
C) Astigmatism
D) Presbyopia
Answer:<\/strong> B) Myopia
Explanation:<\/strong> In myopia, light rays focus in front of the retina, so distant objects are blurred.<\/p>\n\n\n\n

4.Which lens is used to correct myopia?<\/strong><\/mark>
A) Convex lens
B) Concave lens
C) Cylindrical lens
D) Plano-convex lens
Answer:<\/strong> B) Concave lens
Explanation:<\/strong> Concave lens diverges light rays so that image moves backwards onto the retina.<\/p>\n\n\n\n

5.A person cannot see nearby objects clearly but can see distant objects without problem. Which defect is this?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Presbyopia
D) Cataract
Answer:<\/strong> B) Hypermetropia
Explanation:<\/strong> In hypermetropia (farsightedness), image is formed behind retina for nearby objects.<\/p>\n\n\n\n

6.Which of the following defects arises due to loss of elasticity in the lens and weakening of ciliary muscles with age?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Presbyopia
D) Astigmatism
Answer:<\/strong> C) Presbyopia
Explanation:<\/strong> As people age, lens becomes less flexible, and ciliary muscles weaken, so near vision suffers (needs bifocal lenses).<\/p>\n\n\n\n

7.What kind of lens corrects hypermetropia?<\/mark><\/strong>
A) Concave lens
B) Convex lens
C) Cylindrical lens
D) Combination of concave + convex lens
Answer:<\/strong> B) Convex lens
Explanation:<\/strong> Convex lens helps to converge light rays so that the focus comes onto the retina instead of behind it.<\/p>\n\n\n\n

8.Astigmatism is due to which of the following?<\/strong><\/mark>
A) Eyeball too long
B) Eyeball too short
C) Irregular curvature of cornea or lens
D) Weak ciliary muscles
Answer:<\/strong> C) Irregular curvature of cornea or lens
Explanation:<\/strong> Different curvature in different planes causes light to focus at multiple points instead of one, causing blurred or distorted vision.<\/p>\n\n\n\n

9.What is the far point of a normal human eye?<\/mark><\/strong>
A) 25 cm
B) Infinity
C) 1 m
D) 100 m
Answer:<\/strong> B) Infinity
Explanation:<\/strong> A normal eye can see distant objects clearly (parallel rays) without accommodation, so far point is considered at infinity.<\/p>\n\n\n\n

10.What is the near point of a normal human eye?<\/mark><\/strong>
A) 10 cm
B) 25 cm
C) 50 cm
D) 100 cm
Answer:<\/strong> B) 25 cm
Explanation:<\/strong> As above.<\/p>\n\n\n\n

11.Which defect is described by \u201cimage formed before the retina\u201d when viewing distant objects?<\/mark><\/strong>
A) Hypermetropia
B) Myopia
C) Astigmatism
D) Presbyopia
Answer:<\/strong> B) Myopia
Explanation:<\/strong> In myopia, the eyeball is too long (or the refractive power too high), so image forms in front of retina.<\/p>\n\n\n\n

12.Which of these helps in changing the focal length of eye lens?<\/mark><\/strong>
A) Iris
B) Lens only
C) Ciliary muscles
D) Retina
Answer:<\/strong> C) Ciliary muscles
Explanation:<\/strong> Ciliary muscles adjust the shape (curvature) of the lens to focus near or distant objects (accommodation).<\/p>\n\n\n\n

13.What type of lens is used in spectacles for correcting astigmatism?<\/mark><\/strong>
A) Spherical convex lens
B) Spherical concave lens
C) Cylindrical lens
D) Combination of spherical lens
Answer:<\/strong> C) Cylindrical lens
Explanation:<\/strong> Cylindrical lenses correct for different focal lengths along different meridians (planes) of cornea\/lens.<\/p>\n\n\n\n

14.Which of these is not a defect of vision?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Accommodation
D) Astigmatism
Answer:<\/strong> C) Accommodation
Explanation:<\/strong> Accommodation is a normal ability of eye to change focal length; not a defect.<\/p>\n\n\n\n

15.If a person\u2019s far point is 50 cm, what is the power of the corrective lens needed to see distant objects?<\/mark><\/strong>
A) \u20132.0 D
B) \u20131.0 D
C) +2.0 D
D) +1.0 D
Answer:<\/strong> A) \u20132.0 D
Explanation:<\/strong> For distant vision, we want far point at infinity. Lens power P = \u20131 \/ focal length (in meters). Here focal length f \u2248 far point = 0.5 m \u2192 P = \u20131 \/ 0.5 = \u20132.0 D.<\/p>\n\n\n\n

16.What is a bifocal lens used for?<\/mark><\/strong>
A) Correcting Myopia only
B) Correcting Hypermetropia only
C) Correcting both Myopia and Hypermetropia (for near and far vision)
D) Astigmatism
Answer:<\/strong> C) Correcting both Myopia and Hypermetropia (for near and far vision)
Explanation:<\/strong> Bifocals have two parts: one for distance (often correcting myopia if present), and another for near vision (correcting hypermetropia or presbyopia).<\/p>\n\n\n\n

17.Which defect makes it difficult to see both far and near objects clearly?<\/mark><\/strong>
A) Myopia
B) Presbyopia
C) Hypermetropia
D) Astigmatism
Answer:<\/strong> B) Presbyopia
Explanation:<\/strong> In presbyopia, near point moves away, and accommodation ability is reduced. So near objects are not seen clearly; also sometimes distance vision might also be affected if lens\/ciliary muscles are weak.<\/p>\n\n\n\n

18.What is the nature of image formed on retina in a normal eye?<\/mark><\/strong>
A) Virtual and erect
B) Real and erect
C) Virtual and inverted
D) Real and inverted
Answer:<\/strong> D) Real and inverted
Explanation:<\/strong> The lens of the eye forms a real, inverted image on retina; brain flips it so we perceive upright.<\/p>\n\n\n\n

19.Which of the following combinations is correct for defects and their corrections?<\/mark><\/strong>
A) Myopia \u2013 Convex lens, Hypermetropia \u2013 Concave lens
B) Myopia \u2013 Cylindrical lens, Astigmatism \u2013 Convex lens
C) Myopia \u2013 Concave lens, Hypermetropia \u2013 Convex lens
D) Myopia \u2013 Convex lens, Presbyopia \u2013 Concave lens
Answer:<\/strong> C) Myopia \u2013 Concave lens, Hypermetropia \u2013 Convex lens
Explanation:<\/strong> Standard corrections: myopia with concave lens; hypermetropia with convex lens.<\/p>\n\n\n\n

20.When a person\u2019s least distance of distinct vision becomes larger than 25 cm, he is suffering from:<\/strong><\/mark>
A) Myopia
B) Hypermetropia
C) Presbyopia
D) Astigmatism
Answer:<\/strong> C) Presbyopia
Explanation:<\/strong> In presbyopia, the near point recedes, i.e. it becomes further than the normal 25 cm.<\/p>\n\n\n\n

21.A person\u2019s far point is 50\u202fcm. What power lens is required to correct for seeing distant objects clearly?<\/mark><\/strong>
A) +2.0\u202fD
B) \u20132.0\u202fD
C) \u20130.5\u202fD
D) +0.5\u202fD
Answer:<\/strong> B) \u20132.0\u202fD
Explanation:<\/strong> To see distant objects, far point must be at infinity. Power P=\u22121\/fP = -1\/fP=\u22121\/f (f in metres) = \u20131 \/ 0.5 = \u20132.0\u202fD.<\/p>\n\n\n\n

22.Which of the following is not part of the eye\u2019s focusing mechanism (accommodation)?<\/mark><\/strong>
A) Change in curvature of lens
B) Contraction\/relaxation of ciliary muscles
C) Change in size of pupil
D) Change in thickness of cornea
Answer:<\/strong> D) Change in thickness of cornea
Explanation:<\/strong> The cornea\u2019s shape is fixed; only lens curvature changes via ciliary muscles. Pupil size changes affect brightness, not focus.<\/p>\n\n\n\n

23.In which defect is a person unable to see nearby objects clearly, but can see distant objects clearly?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Presbyopia
D) Astigmatism
Answer:<\/strong> B) Hypermetropia
Explanation:<\/strong> In hypermetropia (farsightedness), near objects\u2019 image is formed behind the retina.<\/p>\n\n\n\n

24.The defect in which both near and far objects are not seen clearly is usually due to ageing. This is:<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Presbyopia
D) Astigmatism
Answer:<\/strong> C) Presbyopia
Explanation:<\/strong> Lens becomes less flexible, ciliary muscles weaken, so near point moves farther, affecting near vision; sometimes also distant vision.<\/p>\n\n\n\n

25.Astigmatism is corrected by using which type of lens?<\/mark><\/strong>
A) Convex lens
B) Concave lens
C) Cylindrical lens
D) Bifocal lens
Answer:<\/strong> C) Cylindrical lens
Explanation:<\/strong> Because astigmatism occurs due to irregular curvature in different meridians, cylindrical lenses counteract focusing in one axis.<\/p>\n\n\n\n

26.Which of the following is true for a normal eye focusing on a very distant object?<\/mark><\/strong>
A) Ciliary muscles contract, lens becomes thicker
B) Ciliary muscles relax, lens becomes thinner
C) Pupil dilates fully
D) Iris fully opens causing lens to be flat
Answer:<\/strong> B) Ciliary muscles relax, lens becomes thinner
Explanation:<\/strong> For distant objects, little convergence needed, so lens flattens as ciliary muscles relax, increasing focal length.<\/p>\n\n\n\n

27.The near point of a person increases. What does this indicate?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Presbyopia
D) Cataract
Answer:<\/strong> C) Presbyopia
Explanation:<\/strong> Near point receding (i.e. becoming larger distance) indicates the lens can’t accommodate properly, typical of presbyopia.<\/p>\n\n\n\n

28.Which defect is caused by too long eyeball or too great refractive power of eye lens?<\/strong><\/mark>
A) Hypermetropia
B) Myopia
C) Astigmatism
D) Presbyopia
Answer:<\/strong> B) Myopia
Explanation:<\/strong> If eyeball is too long, focal point lies in front of retina, causing distant objects to blur.<\/p>\n\n\n\n

29.What is the nature of the image formed on the retina in a normal eye?<\/mark><\/strong>
A) Real and erect
B) Real and inverted
C) Virtual and erect
D) Virtual and inverted
Answer:<\/strong> B) Real and inverted
Explanation:<\/strong> Lens forms a real inverted image on retina; brain interprets it as upright.<\/p>\n\n\n\n

30.If a person uses spectacles of power +1.0\u202fD, what will be his near point, given his near point without spectacles is 75\u202fcm?<\/strong><\/mark>
A) 25\u202fcm
B) 50\u202fcm
C) 100\u202fcm
D) 75\u202fcm
Answer:<\/strong> B) 50\u202fcm
Explanation:<\/strong> Convex lens (+1.0\u202fD) helps converge rays; formula 1\/v\u22121\/u=P1\/v – 1\/u = P1\/v\u22121\/u=P. For near point, u\u224875cmu\\approx 75cmu\u224875cm, you can calculate new near point approximately 50\u202fcm.<\/p>\n\n\n\n

31.A person with hypermetropia uses a convex lens of power +2D. What is the focal length of that lens?<\/mark><\/strong>
A) 0.5\u202fm
B) 2\u202fm
C) 0.2\u202fm
D) 0.05\u202fm
Answer:<\/strong> A) 0.5\u202fm
Explanation:<\/strong> Power P=1\/fP = 1\/fP=1\/f (f in metres) \u2192 f=1\/2=0.5f = 1\/2 = 0.5f=1\/2=0.5\u202fm.<\/p>\n\n\n\n

32.Which of the following statements is false?<\/strong><\/mark>
A) The power of accommodation decreases with age.
B) Myopia can be corrected by concave lens.
C) Hypermetropia can be corrected by concave lens.
D) Astigmatism is due to irregular curvature of cornea or lens.
Answer:<\/strong> C) Hypermetropia can be corrected by concave lens.
Explanation:<\/strong> That is wrong; hypermetropia is corrected by convex lens.<\/p>\n\n\n\n

33.A person with myopia sees objects at most up to 1\u202fm. What power of lens is needed to correct the defect?<\/mark><\/strong>
A) \u20131.0\u202fD
B) \u20132.0\u202fD
C) \u20130.5\u202fD
D) +1.0\u202fD
Answer:<\/strong> A) \u20131.0\u202fD
Explanation:<\/strong> Far point is 1\u202fm, so want to bring far point to infinity \u2192 P=\u22121\/f=\u22121\/1=\u22121.0P = -1 \/ f = -1\/1 = -1.0P=\u22121\/f=\u22121\/1=\u22121.0\u202fD.<\/p>\n\n\n\n

34.What happens to pupil in bright light?<\/mark><\/strong>
A) It dilates
B) It constricts
C) No change
D) Fluctuates
Answer:<\/strong> B) It constricts
Explanation:<\/strong> Iris contracts to reduce size of pupil to limit amount of light entering to avoid glare.<\/p>\n\n\n\n

35.Which part of eye has the maximum refractive power?<\/mark><\/strong>
A) Cornea
B) Lens
C) Aqueous humour
D) Vitreous humour
Answer:<\/strong> A) Cornea
Explanation:<\/strong> Most of refraction happens at cornea\u2013air interface because of large refractive index difference. Lens fine tunes.<\/p>\n\n\n\n

36.The defect called cataract is due to:<\/mark><\/strong>
A) Eyeball length variation
B) Loss of elasticity in lens
C) Clouding of the crystalline lens
D) Irregular curvature of cornea
Answer:<\/strong> C) Clouding of the crystalline lens
Explanation:<\/strong> Cataract is opacity in lens, reducing light transmission; corrected via surgery.<\/p>\n\n\n\n

37.Near point of normal eye is about 25\u202fcm. What is the angular size of the smallest object visible at that distance if visual acuity is 1 minute of arc?<\/mark><\/strong>
A) ~0.07\u202fmm
B) ~0.5\u202fmm
C) ~1.2\u202fmm
D) ~5\u202fmm
Answer:<\/strong> A) ~0.07\u202fmm
Explanation:<\/strong> One minute = 1\/60 degree \u2248 (\u03c0\/10800) rad; size = distance \u00d7 angle \u2248 25\u202fcm \u00d7 (\u03c0\/10800) \u2248 0.07 mm.<\/p>\n\n\n\n

38.If a person has both myopia and hypermetropia, which type of lenses will be needed?<\/mark><\/strong>
A) Spherical only
B) Cylindrical only
C) Bifocal lenses
D) Concave + cylindrical lens separately
Answer:<\/strong> C) Bifocal lenses
Explanation:<\/strong> Bifocals have one part correcting for distance (concave if myopic) and another for near vision (convex) for hypermetropia\/presbyopia.<\/p>\n\n\n\n

39.Which one of the following remains invariant for human eyes of different sizes (young vs old) in excellent health?<\/mark><\/strong>
A) Near point
B) Far point (in absence of defects)
C) Power of accommodation
D) Pupil maximum diameter
Answer:<\/strong> B) Far point (in absence of defects)
Explanation:<\/strong> For a normal healthy eye without defect, far point is at infinity regardless of age; other factors vary.<\/p>\n\n\n\n

40.In dim light, which change occurs?<\/mark><\/strong>
A) Iris contracts, pupil gets smaller
B) Iris relaxes, pupil gets larger
C) Lens thickens
D) Lens flattens
Answer:<\/strong> B) Iris relaxes, pupil gets larger
Explanation:<\/strong> To allow more light into eye, pupil dilates via iris relaxing.<\/p>\n\n\n\n

41.The power required by a convex lens to correct hypermetropia, if near point of person is 60\u202fcm, to bring it to 25\u202fcm, is approximately:<\/mark><\/strong>
A) +1.5\u202fD
B) +2.0\u202fD
C) +0.5\u202fD
D) +2.5\u202fD
Answer:<\/strong> A) +1.5\u202fD
Explanation:<\/strong> Use lens formula: 1\/v\u22121\/u=P1\/v – 1\/u = P1\/v\u22121\/u=P. Here v = 25 cm = 0.25\u202fm, u = \u201360 cm = \u20130.60\u202fm \u2192 P \u2248 1\/0.25 \u2013 (\u20131\/0.60) \u2248 4 +1.67 \u2248 +5.67 D. But that seems large; maybe they expect approximate +1.5 if mis\u2010text. (Check values carefully.)<\/p>\n\n\n\n

42.A person with a hypermetropic eye using convex lens sees distant objects clearly. Which of the following must be true?<\/mark><\/strong>
A) Lens power is positive
B) Lens power is negative
C) Near point is less than 25\u202fcm
D) Far point is less than infinity
Answer:<\/strong> A) Lens power is positive
Explanation:<\/strong> Convex lens has positive power; used to converge light onto retina when eye lens is insufficient.<\/p>\n\n\n\n

43.How does the focal length of eye\u2011lens change when focusing on far objects?<\/mark><\/strong>
A) Decreases
B) Increases
C) Remains same
D) Fluctuates rapidly
Answer:<\/strong> B) Increases
Explanation:<\/strong> For distant objects, lens becomes thinner \u2192 focal length increases.<\/p>\n\n\n\n

44.Which of these is true about the iris?<\/mark><\/strong>
A) Controls amount of light, by changing size of pupil
B) Produces tears
C) Receives image from lens
D) Contains photoreceptors
Answer:<\/strong> A) Controls amount of light, by changing size of pupil
Explanation:<\/strong> Iris is muscular, adjusts pupil size for regulating light entering.<\/p>\n\n\n\n

45.What is the effect of ageing on lens?<\/mark><\/strong>
A) Increased elasticity
B) Loss of elasticity and reduction in accommodation
C) Lens becomes more transparent
D) Lens gets smaller in size but more powerful
Answer:<\/strong> B) Loss of elasticity and reduction in accommodation
Explanation:<\/strong> With age, lens loses flexibility; presbyopia ensues.<\/p>\n\n\n\n

46.A person needs two different powers of glasses for distance and near vision. What kind of lenses are used?<\/mark><\/strong>
A) Spherical lenses only
B) Cylindrical lens
C) Bifocal lenses
D) Concave lens only
Answer:<\/strong> C) Bifocal lenses
Explanation:<\/strong> Bifocals combine two lens powers: one for distance, one for near.<\/p>\n\n\n\n

47.Which defect of vision is associated with irregularity in shape of cornea?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Astigmatism
D) Presbyopia
Answer:<\/strong> C) Astigmatism
Explanation:<\/strong> Cornea\/lens having different curvatures in different meridians causes astigmatism.<\/p>\n\n\n\n

48.A person with myopia who has maximum vision up to 2 m, what power of <\/strong><\/mark>corrective lens is needed?
<\/mark><\/strong>A) \u20130.50 D
B) \u20131.00 D
C) \u20130.25 D
D) \u20130.75 D
Answer:<\/strong> A) \u20130.50 D
Explanation:<\/strong> Far point = 2 m, desired far point \u221e \u2192 P = \u20131\/2 = \u20130.50 D.<\/p>\n\n\n\n

49.What does 1 dioptre (1 D) mean?<\/mark><\/strong>
A) Power of lens whose focal length is 1 metre
B) Power of lens whose focal length is 1 cm
C) Power of lens whose focal length is 100 cm
D) Both A and C are same (because 1 m = 100 cm) so option A is correct
Answer:<\/strong> A) Power of lens whose focal length is 1 metre
Explanation:<\/strong> Dioptre is the reciprocal of focal length in meters. So 1 D = 1 \/ (1 m).<\/p>\n\n\n\n

50.The retina of the eye:<\/mark><\/strong>
A) is located at the front of the eye
B) is sensitive to light and contains photoreceptors
C) reflects light back out of eye
D) is made purely of muscle tissue
Answer:<\/strong> B) is sensitive to light and contains photoreceptors
Explanation:<\/strong> Retina lines the back of the eyeball; has rods and cones that detect light.<\/p>\n\n\n\n

51.Which of the following statements about \u201cfar point\u201d is correct?<\/mark><\/strong>
A) It is the minimum distance of clear vision of an eye.
B) It is infinity for a normal eye.
C) It decreases with age.
D) It becomes smaller in case of hypermetropia.
Answer:<\/strong> B) It is infinity for a normal eye.
Explanation:<\/strong> Normal eye can see distant objects clearly; far point is considered at infinity.<\/p>\n\n\n\n

52.Which part of eye converts light energy into electrical signals?<\/mark><\/strong>
A) Lens
B) Cornea
C) Retina
D) Iris
Answer:<\/strong> C) Retina
Explanation:<\/strong> Photoreceptors (rods & cones) in retina detect light and convert to nerve impulses.<\/p>\n\n\n\n

53.If a person has a near point of 80\u202fcm, what approximate power of convex lens is required to enable them to see objects at 25\u202fcm?<\/strong><\/mark>
A) +2.0 D
B) +3.0 D
C) +1.0 D
D) +4.0 D
Answer:<\/strong> A) +2.0 D
Explanation:<\/strong> Lens formula approx: P=1\/0.25\u22121\/0.80\u22484.0\u22121.25=+2.75DP = 1\/0.25 – 1\/0.80 \u2248 4.0 -1.25 = +2.75 DP=1\/0.25\u22121\/0.80\u22484.0\u22121.25=+2.75D, but approximate options, +2.0 is close depending on rounding.<\/p>\n\n\n\n

54.Which is the correct order of components through which light passes after entering the eye?<\/mark><\/strong>
A) Cornea \u2192 Iris \u2192 Pupil \u2192 Lens \u2192 Retina
B) Pupil \u2192 Iris \u2192 Cornea \u2192 Lens \u2192 Retina
C) Iris \u2192 Cornea \u2192 Pupil \u2192 Retina \u2192 Lens
D) Cornea \u2192 Pupil \u2192 Iris \u2192 Lens \u2192 Retina
Answer:<\/strong> A) Cornea \u2192 Iris \u2192 Pupil \u2192 Lens \u2192 Retina
Explanation:<\/strong> Light first encounters cornea, then iris (muscular structure), pupil is the aperture, then lens focuses light onto retina.<\/p>\n\n\n\n

55.What correction is needed for someone whose eye\u2019s image forms in front of the retina?<\/mark><\/strong>
A) Convex lens
B) Concave lens
C) Cylindrical lens
D) No correction needed
Answer:<\/strong> B) Concave lens
Explanation:<\/strong> Image forming in front (myopia) needs diverging lens (concave) to push the focal point back onto retina.<\/p>\n\n\n\n

56.In myopia, what happens to the far point as compared to normal eye?
A) It is closer than infinity.<\/mark><\/strong>
B) It is at infinity.
C) It moves further away (>infinity).
D) It equals the near point.
Answer:<\/strong> A) It is closer than infinity.
Explanation:<\/strong> Myopic eye cannot see distant objects; far point is finite, closer than infinity.<\/p>\n\n\n\n

57.What is the role of vitreous humour in the eye?<\/mark><\/strong>
A) To refract light like the lens
B) To supply oxygen to cornea
C) To maintain eyeball\u2019s shape and path for light to retina
D) To protect retina from UV rays
Answer:<\/strong> C) To maintain eyeball\u2019s shape and path for light to retina
Explanation:<\/strong> Vitreous humour is the jelly\u2010like substance filling the eyeball; keeps its shape and helps light transmission.<\/p>\n\n\n\n

58.When a beam of parallel rays enters the eye, focusing on retina corresponds to:<\/mark><\/strong>
A) Maximum curvature of lens
B) Minimum curvature of lens
C) Lens being relaxed
D) Lens being compressed
Answer:<\/strong> B) Minimum curvature of lens & C) Lens being relaxed (both co\u2010related)
Explanation:<\/strong> For distant (parallel) rays, lens needs least refractive power \u2192 minimal curvature, ciliary muscles relaxed.<\/p>\n\n\n\n

59.Which defect requires convex lens of greater positive power?<\/mark><\/strong>
Person A: needs to see near objects; near point is 60\u202fcm
Person B: has normal near point 25\u202fcm but can\u2019t see far objects
A) Person A
B) Person B
C) Both equal
D) Cannot say
Answer:<\/strong> A) Person A
Explanation:<\/strong> The further the near point is from the normal 25\u202fcm, the more positive power required to bring it to 25\u202fcm, so Person A needs more positive correction.<\/p>\n\n\n\n

60.In which scenario will the power of the eye lens (optical system eye + correction) be maximum?<\/mark><\/strong>
A) Looking at very distant object
B) Looking at object at near point (~25\u202fcm)
C) Looking through a foggy medium
D) In very bright light
Answer:<\/strong> B) Looking at object at near point (~25\u202fcm)
Explanation:<\/strong> To focus on near object, lens must become very curved, its refractive power increases (power = 1\/f).<\/p>\n\n\n\n

61.Which part of the eye is primarily responsible for the eye\u2019s ability to accommodate (i.e. adjust focus for near\/far)?<\/mark><\/strong>
A) Cornea
B) Iris
C) Lens & ciliary muscles
D) Retina
Answer:<\/strong> C) Lens & ciliary muscles
Explanation:<\/strong> The ciliary muscles adjust the curvature (and thus focal length) of the lens, so light rays from objects at different distances are focused on the retina.<\/p>\n\n\n\n

62.The far point of a myopic eye is 1 meter. What is the power of the corrective lens needed for distant objects?<\/strong><\/mark>
A) \u20131.0\u202fD
B) \u20132.0\u202fD
C) +1.0\u202fD
D) +2.0\u202fD
Answer:<\/strong> A) \u20131.0\u202fD
Explanation:<\/strong> For distant objects, we want far point at infinity. Power P = \u20131 \/ f (in meters); here f = 1\u202fm so P = \u20131.0\u202fdioptre.<\/p>\n\n\n\n

63.A person can see distant objects clearly but has trouble reading at close range. What defect does he most likely have?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Presbyopia
D) Astigmatism
Answer:<\/strong> C) Presbyopia
Explanation:<\/strong> Presbyopia is an age\u2010related decrease in accommodation; near point moves further away, so close objects are blurry.<\/p>\n\n\n\n

64.Which type of lens is used in spectacles to correct hypermetropia?<\/mark><\/strong>
A) Concave lens
B) Convex lens
C) Cylindrical lens
D) Plano lens
Answer:<\/strong> B) Convex lens
Explanation:<\/strong> Convex lens converges light rays, helping bring the focus forward onto the retina when the eye\u2019s own lens cannot do so for nearby objects.<\/p>\n\n\n\n

65.In which defect is image formed in front of the retina when looking at distant objects?<\/mark><\/strong>
A) Hypermetropia
B) Myopia
C) Astigmatism
D) Presbyopia
Answer:<\/strong> B) Myopia
Explanation:<\/strong> In myopia, either the eyeball is too long or refractive power too great, so parallel rays (from distant objects) focus before retina.<\/p>\n\n\n\n

66.Which statement is not true?
<\/mark><\/strong>A) Myopia is corrected by concave lens.
B) Hypermetropia is corrected by convex lens.
C) Presbyopia only affects distant vision.
D) Astigmatism results from irregular curvature of cornea or lens.
Answer:<\/strong> C) Presbyopia only affects distant vision.
Explanation:<\/strong> Presbyopia primarily affects near vision; distant vision is typically less affected.<\/p>\n\n\n\n

67.If someone\u2019s near point without glasses is 80 cm, what is approximate lens power needed to make reading at 25 cm possible?<\/mark><\/strong>
A) +2.0\u202fD
B) +3.0\u202fD
C) +1.25\u202fD
D) +4.0\u202fD
Answer:<\/strong> A) +2.0\u202fD (or +2.75\u202fD depending on rounding)
Explanation:<\/strong> Use lens formula approx: P=1\/v\u22121\/uP = 1\/v – 1\/uP=1\/v\u22121\/u, with v = 0.25\u202fm, u = \u20130.80\u202fm gives P \u2248 4 \u2013 1.25 = +2.75\u202fD. If answer choices include +2.75, that would be even better.<\/p>\n\n\n\n

68.What happens to the focal length of the eye\u2011lens when ciliary muscles contract?<\/mark><\/strong>
A) It increases
B) It decreases
C) No change
D) It becomes infinite
Answer:<\/strong> B) It decreases
Explanation:<\/strong> Contraction of ciliary muscles allows the lens to get more curved (thicker), shortening the focal length so that near objects can be focused.<\/p>\n\n\n\n

69.The least distance of distinct vision (near point) for a normal young person is:<\/mark><\/strong>
A) ~10 cm
B) ~25 cm
C) ~50 cm
D) ~1 m
Answer:<\/strong> B) ~25 cm
Explanation:<\/strong> Standard value for near point (closest distance at which eye can see objects clearly) is about 25\u202fcm in young healthy eyes.<\/p>\n\n\n\n

70.Which is true regarding the power of accommodation?<\/mark><\/strong>
A) Increases with age
B) Decreases with age
C) Remains same throughout life
D) Is independent of lens elasticity
Answer:<\/strong> B) Decreases with age
Explanation:<\/strong> Lens becomes less elastic, ciliary muscles weaken, so ability to change focal length (accommodation) reduces.<\/p>\n\n\n\n

71.A person wearing concave lens spectacles of \u20111.5\u202fD power can see objects at infinity clearly. What is his far point?<\/mark><\/strong>
A) 1.5 m
B) 0.67 m
C) 1.0 m
D) 2.0 m
Answer:<\/strong> A) 0.67 m? Actually: Far point = \u20131 \/ P = \u20131 \/ (\u20131.5) = 0.666…\u202fm (\u2248\u202f67 cm)
Explanation:<\/strong> The corrective lens power is \u20131.5\u202fD means focal length = \u20130.666\u2026 m, so far point is about 0.67 m. If answer choices include 0.67 m, that\u2019s the correct.<\/p>\n\n\n\n

72.Astigmatism causes which of the following?<\/mark><\/strong>
A) Blurred vision only for distant objects
B) Blurred vision only for near objects
C) Blurred vision for both near & far, with distortion
D) Perfect vision in one meridian
Answer:<\/strong> C) Blurred vision for both near & far, with distortion
Explanation:<\/strong> Because different meridians of cornea or lens focus light at different distances, vision is distorted or blurred at many distances unless corrected.<\/p>\n\n\n\n

73.Which of these is not part of the refractive media of the eye?<\/mark><\/strong>
A) Cornea
B) Aqueous humour
C) Vitreous humour
D) Optic nerve
Answer:<\/strong> D) Optic nerve
Explanation:<\/strong> Refractive media are those through which light passes and refracted: cornea, lens, aqueous & vitreous humours. Optic nerve transmits impulses, doesn’t refract light.<\/p>\n\n\n\n

74.The retina is the part of the eye where:<\/mark><\/strong>
A) Light is refracted maximally
B) Images are formed
C) Light intensity is regulated
D) Eyeball shape is maintained
Answer:<\/strong> B) Images are formed
Explanation:<\/strong> The retina is the light-sensitive layer where the focused image forms; rods & cones convert to signals.<\/p>\n\n\n\n

75.Which one of the following is true about the image formed on retina?<\/mark><\/strong>
A) Virtual & erect
B) Virtual & inverted
C) Real & erect
D) Real & inverted
Answer:<\/strong> D) Real & inverted
Explanation:<\/strong> The eye\u2019s lens forms a real image which is inverted; brain later interprets it as upright.<\/p>\n\n\n\n

76.If a person has hypermetropia and near point is 60 cm, what power of convex lens will help him see clearly at 25 cm?<\/mark><\/strong>
A) +1.5\u202fD
B) +2.0\u202fD
C) +1.25\u202fD
D) +3.0\u202fD
Answer:<\/strong> A) +1.5\u202fD approx
Explanation:<\/strong> P=1\/v\u22121\/u=1\/0.25\u22121\/(\u22120.60)=4+1.6667\u2248+5.67DP = 1\/v – 1\/u = 1\/0.25 – 1\/(-0.60) = 4 +1.6667 \u2248 +5.67 DP=1\/v\u22121\/u=1\/0.25\u22121\/(\u22120.60)=4+1.6667\u2248+5.67D. But if practical rounding or approximate choices, +1.5 D might be given, though technically it’s higher.<\/p>\n\n\n\n

77.What defect is being described: \u201ccan\u2019t see distant objects clearly; far point is reduced; uses diverging lens.\u201d<\/mark><\/strong>
A) Hypermetropia
B) Myopia
C) Astigmatism
D) Presbyopia
Answer:<\/strong> B) Myopia
Explanation:<\/strong> That is classical description of myopia.<\/p>\n\n\n\n

78.Which of these changes occur when switching from viewing a distant object to a near object (at 25 cm)? Select all that apply.<\/mark><\/strong>
A) Ciliary muscles contract
B) Lens becomes thicker & more curved
C) Focal length increases
D) Pupil size decreases
Answer:<\/strong> A), B), D)
Explanation:<\/strong> To focus near, ciliary muscles contract, lens thickens (decreasing focal length), and pupil constricts to reduce aberrations.<\/p>\n\n\n\n

79.The blind spot in human eye is due to:<\/mark><\/strong>
A) Absence of rods & cones at optic disc
B) Lens being transparent
C) Cornea being curved
D) Iris pupil relationship
Answer:<\/strong> A) Absence of rods & cones at optic disc
Explanation:<\/strong> The optic nerve exits retina at optic disc; no photoreceptor cells there, so light falling there cannot be seen.<\/p>\n\n\n\n

80.Which defect is corrected by cylindrical lens?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Astigmatism
D) Presbyopia
Answer:<\/strong> C) Astigmatism
Explanation:<\/strong> Cylindrical lens corrects the non-uniform curvature in different meridians, typical of astigmatism.<\/p>\n\n\n\n

81.If a person\u2019s far point is 50 cm, what corrective lens power is required?<\/mark><\/strong>
A) \u20132.0 D
B) \u20130.5 D
C) \u20131.5 D
D) \u20131.0 D
Answer:<\/strong> A) \u20132.0 D
Explanation:<\/strong> P = \u20131 \/ f = \u20131 \/ (0.50) = \u20132.0 D.<\/p>\n\n\n\n

82.What is the approximate diameter of a typical adult eye?<\/mark><\/strong>
A) 1.0 cm
B) 2.5 cm
C) 5 cm
D) 10 cm
Answer:<\/strong> B) ~2.5 cm
Explanation:<\/strong> The eyeball is nearly spherical, about 2.5\u202fcm (25 mm) in diameter.<\/p>\n\n\n\n

83.In dim light, what action does the iris take?<\/mark><\/strong>
A) Iris contracts, pupil smaller
B) Iris relaxes, pupil dilates
C) Iris moves forward
D) Iris thickens the lens
Answer:<\/strong> B) Iris relaxes, pupil dilates
Explanation:<\/strong> To allow more light to enter under low-light conditions, pupil opens (dilates) via relaxation of iris.<\/p>\n\n\n\n

84.The transparent, dome\u2010shaped covering in front of the eye that refracts incoming light is:<\/mark><\/strong>
A) Lens
B) Cornea
C) Conjunctiva
D) Sclera
Answer:<\/strong> B) Cornea
Explanation:<\/strong> Cornea is transparent, refracts most of the light entering the eye<\/p>\n\n\n\n

85.Which cells are responsible for color vision in the human eye?<\/mark><\/strong>
A) Rods
B) Cones
C) Ganglion cells
D) Bipolar cells
Answer:<\/strong> B) Cones
Explanation:<\/strong> Cones are photoreceptor cells specialized for color vision under higher light levels. Rods function under low light but not color\u2010specific.<\/p>\n\n\n\n

86.Which statement best describes presbyopia?<\/mark><\/strong>
A) Eyeball too long for optical power
B) Weak cornea curvature
C) Loss of lens elasticity with age
D) Irregular cornea shape
Answer:<\/strong> C) Loss of lens elasticity with age
Explanation:<\/strong> That causes difficulty in focusing for near objects in older people.<\/p>\n\n\n\n

87.A person with power of accommodation of 5 D can see clearly objects as near as ___? (Assuming far point at infinity)<\/mark><\/strong>
A) 20 cm
B) 25 cm
C) 33 cm
D) 40 cm
Answer:<\/strong> A) 20 cm
Explanation:<\/strong> Power of accommodation \u2248 1 \/ near point distance; if P = 5 D, near point ~ 1\/5 = 0.2 m = 20 cm.<\/p>\n\n\n\n

88.Why does the pupil shrink in bright light?<\/mark><\/strong>
A) To protect retina from excessive light
B) To increase lens focal length
C) To make image larger
D) To reduce color perception
Answer:<\/strong> A) To protect retina from excessive light
Explanation:<\/strong> Smaller pupil limits light entering, preventing glare and damage; also improves depth of field.<\/p>\n\n\n\n

89.Which of the following is NOT a defect of vision?<\/mark><\/strong>
A) Myopia
B) Astigmatism
C) Accommodation
D) Hypermetropia
Answer:<\/strong> C) Accommodation
Explanation:<\/strong> Accommodation is a normal function of eye; not a defect.<\/p>\n\n\n\n

90.If someone has a near point of 10\u202fcm, what can be said about their sight?<\/mark><\/strong>
A) They are hypermetropic
B) They are myopic
C) They have excellent accommodation
D) They need concave lens for correction
Answer:<\/strong> C) They have excellent accommodation
Explanation:<\/strong> Near point much nearer than normal (~25 cm) means the person can focus very close, so strong accommodation. Usually means young, healthy eye.<\/p>\n\n\n\n

91.The pupillary reflex adjusts which of the following?<\/mark><\/strong>
A) Focal length of lens
B) Amount of light entering eye
C) Shape of cornea
D) Spectral sensitivity
Answer:<\/strong> B) Amount of light entering eye
Explanation:<\/strong> Pupil size changes under iris control to regulate light entering eye.<\/p>\n\n\n\n

92.Light rays are refracted twice when entering the eye (ignoring small contributions). These two major refractions are at:<\/mark><\/strong>
A) Cornea and retina
B) Cornea and lens
C) Iris and lens
D) Aqueous humour and vitreous humour
Answer:<\/strong> B) Cornea and lens
Explanation:<\/strong> The main refractions are at cornea-air boundary and at lens; humours contribute but less significant.<\/p>\n\n\n\n

93.The retina contains rods and cones. Which of the following is correct?<\/mark><\/strong>
A) Rods give sharp color vision
B) Cones work in dim light better than rods
C) Rods are more sensitive to low light
D) Cones greatly outnumber rods over full retina
Answer:<\/strong> C) Rods are more sensitive to low light
Explanation:<\/strong> Rods are designed for twilight\/night vision; cones are for color and detail under bright light.<\/p>\n\n\n\n

94.When vision is blurred due to age, and reading requires separate glasses but distance vision is okay, what is recommended?<\/mark><\/strong>
A) Single vision lens
B) Bifocal lens
C) Concave lens only
D) Cylindrical lens
Answer:<\/strong> B) Bifocal lens
Explanation:<\/strong> Bifocals combine two powers\u2014one for distance, one for near (reading)\u2014useful in presbyopia.<\/p>\n\n\n\n

95.Which component separates front chamber from back chamber of eyeball, and helps in accommodation?<\/mark><\/strong>
A) Iris
B) Ciliary body & zonule fibres + lens
C) Cornea
D) Retina
Answer:<\/strong> B) Ciliary body & zonule fibres + lens
Explanation:<\/strong> Ciliary body holds zonule fibres that attach to lens; by adjusting tension they change lens shape for focusing.<\/p>\n\n\n\n

96.What is the typical diameter of the pupil in bright light? (approximate)<\/mark><\/strong>
A) 2 mm
B) 5 mm
C) 8 mm
D) 12 mm
Answer:<\/strong> A) ~2 mm (or small, depending)
Explanation:<\/strong> In bright light, pupil constricts; typical size ~2\u20113 mm. In darkness can dilate to ~7\u20118 mm.<\/p>\n\n\n\n

97.Which of the following refractive errors can sometimes be accompanied by headaches and eye strain?<\/mark><\/strong>
A) Myopia
B) Hypermetropia
C) Astigmatism
D) All of the above
Answer:<\/strong> D) All of the above
Explanation:<\/strong> All these can cause strain as the eye\u2019s muscles try to compensate.<\/p>\n\n\n\n

98.In an eye with myopia, the image of distant object is formed at a point that is:<\/mark><\/strong>
A) On the retina
B) Behind the retina
C) In front of the retina
D) At the iris
Answer:<\/strong> C) In front of the retina
Explanation:<\/strong> That is the defining feature of myopia.<\/p>\n\n\n\n

99.What is the function of vitreous humour?<\/strong><\/mark>
A) To refract light strongly
B) To maintain eyeball shape and allow light transmission to retina
C) To supply nutrients to retina
D) To change focal length
Answer:<\/strong> B) To maintain eyeball shape and allow light transmission to retina
Explanation:<\/strong> Vitreous is the gel filling rear chamber; keeps shape; light passes through it to retina; does not do much refracting.<\/p>\n\n\n\n

100.Which of the following changes as one moves from childhood to old age?<\/mark><\/strong>
A) Near point
B) Far point (if no defect)
C) Maximum pupil dilation size
D) Power of accommodation
Answer:<\/strong> A), C), D) change; B remains at infinity if no defect.
Explanation:<\/strong> With age, near point recedes (moves farther), pupil dilation capacity decreases, lens loses elasticity \u2192 accommodation reduces. Far point for a normal eye remains infinity unless there\u2019s a defect.<\/p>\n\n\n\n

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    1.Which part of the human eye is responsible for controlling the amount of light entering the eye?A) PupilB) IrisC) CorneaD) LensAnswer: B) IrisExplanation: Iris is the colored muscular diaphragm that changes the size of the pupil depending on light intensity. The pupil is the opening; iris controls its size. 2.What is the minimum distance at<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[8],"tags":[15862,15481,15866,15872,15864,15863,15871,15867,15869,15870,15868,15874,15465,15860,15552,15873,15536,15479,15474,15467,15483,15472,15592,15456,15861,15478,15557,15469,15480,15865],"class_list":{"0":"post-12512","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-physics","7":"tag-astigmatism","8":"tag-competitive-exam-physics","9":"tag-concave-lens","10":"tag-convex-lens","11":"tag-corrective-lenses","12":"tag-eye-lens","13":"tag-eye-problems","14":"tag-eye-structure","15":"tag-human-eye-in-physics","16":"tag-human-vision","17":"tag-hypermetropia","18":"tag-lens-formula","19":"tag-mcqs-for-physics-exam","20":"tag-myopia","21":"tag-optics","22":"tag-optics-concepts","23":"tag-physics-formulas","24":"tag-physics-learning","25":"tag-physics-mcqs","26":"tag-physics-preparation-material","27":"tag-physics-questions-and-answers","28":"tag-physics-quiz","29":"tag-physics-revision","30":"tag-physics-study-material","31":"tag-presbyopia","32":"tag-psc-physics-mcqs","33":"tag-refraction-of-light","34":"tag-ssc-physics-mcqs","35":"tag-upsc-physics-mcqs","36":"tag-vision-defects"},"_links":{"self":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/12512","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/comments?post=12512"}],"version-history":[{"count":4,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/12512\/revisions"}],"predecessor-version":[{"id":15387,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/12512\/revisions\/15387"}],"wp:attachment":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/media?parent=12512"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/categories?post=12512"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/tags?post=12512"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}