{"id":12567,"date":"2025-09-19T05:25:35","date_gmt":"2025-09-19T04:25:35","guid":{"rendered":"https:\/\/mcqsadda.com\/?p=12567"},"modified":"2025-10-21T07:42:22","modified_gmt":"2025-10-21T06:42:22","slug":"interest-top-100-mcqs-with-answer-and-explanation","status":"publish","type":"post","link":"https:\/\/mcqsadda.com\/index.php\/2025\/09\/19\/interest-top-100-mcqs-with-answer-and-explanation\/","title":{"rendered":"Interest Top 100 MCQs With Answer and Explanation"},"content":{"rendered":"\n

1. What will be the simple interest on \u20b95000 at 12% per annum for 2 years?<\/mark><\/strong>
a) \u20b91000
b) \u20b91100
c) \u20b91200
d) \u20b91250
Answer:<\/strong> c) \u20b91200
Explanation:<\/strong> SI = (P \u00d7 R \u00d7 T) \/ 100 = (5000 \u00d7 12 \u00d7 2)\/100 = 1200.<\/p>\n\n\n\n

2. A sum of \u20b9800 amounts to \u20b9920 in 3 years at simple interest. The rate of interest is:<\/mark><\/strong>
a) 4%
b) 5%
c) 6%
d) 7%
Answer:<\/strong> b) 5%
Explanation:<\/strong> SI = 920 \u2013 800 = 120. \u2192 R = (100\u00d7120)\/(800\u00d73) = 5%.<\/p>\n\n\n\n

3. At what rate of interest will \u20b94000 amount to \u20b94600 in 3 years at simple interest?<\/mark><\/strong>
a) 4%
b) 5%
c) 6%
d) 7%
Answer: <\/strong>b) 5%
Explanation:<\/strong> SI = 600. \u2192 R = (100\u00d7600)\/(4000\u00d73) = 5%.<\/p>\n\n\n\n

4. The SI on a sum of money is 1\/9 of the principal. The rate \u00d7 time is:<\/mark><\/strong>
a) 5%
b) 9%
c) 11.11%
d) 100\/9 %
Answer: <\/strong>d) 100\/9 %
Explanation:<\/strong> SI = (P\u00d7R\u00d7T)\/100 = P\/9 \u2192 RT = 100\/9.<\/p>\n\n\n\n

5. A sum doubles itself in 10 years at SI. The rate of interest is:<\/mark><\/strong>
a) 5%
b) 7%
c) 8%
d) 10%
Answer: <\/strong>d) 10%
Explanation:<\/strong> SI = P \u2192 (P\u00d7R\u00d710)\/100 = P \u2192 R = 10%.<\/p>\n\n\n\n

6. At 12% per annum, how many years will a sum of money double itself at SI?<\/mark><\/strong>
a) 6 years
b) 7 years
c) 8.33 years
d) 9 years
Answer: <\/strong>c) 8.33 years
Explanation:<\/strong> SI = P \u2192 (P\u00d712\u00d7T)\/100 = P \u2192 T = 100\/12 = 8.33 years.<\/p>\n\n\n\n

7. What will be the SI on \u20b92500 for 4 years at 8% per annum?<\/mark><\/strong>
a) \u20b9600
b) \u20b9700
c) \u20b9750
d) \u20b9800
Answer: <\/strong>d) \u20b9800
Explanation:<\/strong> SI = (2500\u00d78\u00d74)\/100 = 800.<\/p>\n\n\n\n

8. A sum of \u20b9500 amounts to \u20b9650 in 4 years at SI. The rate % is:<\/mark><\/strong>
a) 5%
b) 6%
c) 7.5%
d) 8%
Answer:<\/strong> c) 7.5%
Explanation:<\/strong> SI = 150 \u2192 R = (100\u00d7150)\/(500\u00d74) = 7.5%.<\/p>\n\n\n\n

9. The SI on a sum for 5 years is one-fourth of the principal. The rate % is:<\/mark><\/strong>
a) 4%
b) 5%
c) 6%
d) 8%
Answer: <\/strong>b) 5%
Explanation:<\/strong> (P\u00d7R\u00d75)\/100 = P\/4 \u2192 R = 5%.<\/p>\n\n\n\n

10. Find the SI on \u20b94000 at 5% per annum for 3 years.<\/mark><\/strong>
a) \u20b9500
b) \u20b9550
c) \u20b9600
d) \u20b9700
Answer: <\/strong>c) \u20b9600
Explanation:<\/strong> (4000\u00d75\u00d73)\/100 = 600.<\/p>\n\n\n\n

11. At what rate % will a sum of \u20b92400 yield SI of \u20b9864 in 6 years?<\/mark><\/strong>
a) 5%
b) 6%
c) 7%
d) 8%
Answer: <\/strong>d) 6%
Explanation:<\/strong> R = (100\u00d7864)\/(2400\u00d76) = 6%.<\/p>\n\n\n\n

12. A sum trebles itself in 20 years at SI. The rate of interest is:<\/mark><\/strong>
a) 5%
b) 10%
c) 12%
d) 15%
Answer: <\/strong>a) 10%
Explanation:<\/strong> SI = 2P \u2192 (P\u00d7R\u00d720)\/100 = 2P \u2192 R = 10%.<\/p>\n\n\n\n

13. If the SI on \u20b9500 for 3 years is \u20b9180, what is the rate of interest?<\/mark><\/strong>
a) 10%
b) 11%
c) 12%
d) 13%
Answer:<\/strong> c) 12%
Explanation:<\/strong> (500\u00d7R\u00d73)\/100 = 180 \u2192 R = 12%.<\/p>\n\n\n\n

14. If SI on \u20b91000 for 3 years at R% is \u20b9360, then R is:<\/mark><\/strong>
a) 10%
b) 11%
c) 12%
d) 13%
Answer: <\/strong>c) 12%
Explanation:<\/strong> (1000\u00d7R\u00d73)\/100 = 360 \u2192 R = 12%.<\/p>\n\n\n\n

15. In how many years will \u20b92000 double itself at 10% SI?<\/mark><\/strong>
a) 5 years
b) 8 years
c) 10 years
d) 12 years
Answer:<\/strong> c) 10 years
Explanation:<\/strong> SI = P \u2192 (2000\u00d710\u00d7T)\/100 = 2000 \u2192 T = 10.<\/p>\n\n\n\n

16. A sum of \u20b96000 amounts to \u20b99000 in 5 years at SI. The rate is<\/mark><\/strong>:
a) 8%
b) 9%
c) 10%
d) 12%
Answer:<\/strong> c) 10%
Explanation:<\/strong> SI = 3000 \u2192 R = (100\u00d73000)\/(6000\u00d75) = 10%.<\/p>\n\n\n\n

17. What is the CI on \u20b91000 at 10% p.a. for 2 years (compounded annually)?<\/mark><\/strong>
a) \u20b9200
b) \u20b9210
c) \u20b9220
d) \u20b9230
Answer: <\/strong>b) \u20b9210
Explanation:<\/strong> A = 1000(1+10\/100)\u00b2 = 1210 \u2192 CI = 210.<\/p>\n\n\n\n

18. The CI on a sum of \u20b98000 at 10% for 2 years is:<\/mark><\/strong>
a) \u20b91600
b) \u20b91650
c) \u20b91680
d) \u20b91700
Answer: <\/strong>b) \u20b91680
Explanation:<\/strong> A = 8000(1.1)\u00b2 = 9680 \u2192 CI = 1680.<\/p>\n\n\n\n

19. If \u20b910000 becomes \u20b912100 in 2 years at CI, the rate is:<\/mark><\/strong>
a) 8%
b) 9%
c) 10%
d) 11%
Answer: <\/strong>c) 10%
Explanation:<\/strong> A\/P = 12100\/10000 = 1.21 \u2192 (1+R\/100)\u00b2 = 1.21 \u2192 R = 10%.<\/p>\n\n\n\n

20. The CI on \u20b95000 for 2 years at 10% compounded annually is:<\/mark><\/strong>
a) \u20b91000
b) \u20b91050
c) \u20b91100
d) \u20b91150
Answer: <\/strong>b) \u20b91050
Explanation:<\/strong> A = 5000\u00d7(1.1)\u00b2 = 6050 \u2192 CI = 1050.<\/p>\n\n\n\n

21. The difference between CI and SI on \u20b95000 at 10% for 2 years is:<\/mark><\/strong>
a) \u20b940
b) \u20b945
c) \u20b950
d) \u20b955
Answer: <\/strong>c) \u20b950
Explanation:<\/strong> SI = 1000, CI = 1050 \u2192 Difference = 50.<\/p>\n\n\n\n

22. At what rate % will a sum of money double in 8 years at CI (compounded annually)?<\/mark><\/strong>
a) 8.66%
b) 9%
c) 9.5%
d) 10%
Answer: <\/strong>b) 9%
Explanation:<\/strong> (1+R\/100)\u2078 = 2 \u2192 R \u2248 9%.<\/p>\n\n\n\n

23. A sum becomes \u20b91331 in 3 years at CI. If the principal is \u20b91000, the rate is:<\/mark><\/strong>
a) 8%
b) 9%
c) 10%
d) 11%
Answer: <\/strong>d) 10%
Explanation:<\/strong> (1+R\/100)\u00b3 = 1331\/1000 = 1.331 \u2192 R = 10%.<\/p>\n\n\n\n

24. The CI on \u20b92000 at 5% p.a. for 3 years is:<\/mark><\/strong>
a) \u20b9300
b) \u20b9315.25
c) \u20b9320
d) \u20b9325.25
Answer:<\/strong> b) \u20b9315.25
Explanation:<\/strong> A = 2000(1.05)\u00b3 = 2315.25 \u2192 CI = 315.25.<\/p>\n\n\n\n

25. The difference between CI and SI on \u20b94000 at 5% for 2 years is:<\/mark><\/strong>
a) \u20b95
b) \u20b98
c) \u20b910
d) \u20b912
Answer:<\/mark><\/strong> <\/strong><\/mark>c) \u20b910<\/mark>
Explanation: <\/mark><\/strong>SI = 400, CI = 410 \u2192 Difference = 10.<\/p>\n\n\n\n

26. What will be the CI on \u20b910,000 at 20% per annum for 2 years?<\/mark><\/strong>
a) \u20b94000
b) \u20b94200
c) \u20b94400
d) \u20b94600
Answer:<\/strong> b) \u20b94200
Explanation:<\/strong> A = 10000(1.2)\u00b2 = 14400 \u2192 CI = 4400. Wait correction: 14400 \u2013 10000 = 4400. Correct Answer = <\/strong>c) \u20b94400.<\/p>\n\n\n\n

27. Find the difference between CI and SI on \u20b95000 at 8% per annum for 2 years.<\/mark><\/strong>
a) \u20b916
b) \u20b920
c) \u20b925
d) \u20b930
Answer: <\/strong>c) \u20b920
Explanation:<\/strong> SI = 800. CI = 5000(1.08)\u00b2 \u2013 5000 = 832 \u2013 800 = 20 difference.<\/p>\n\n\n\n

28. The CI on a sum of \u20b912,000 at 10% p.a. for 2 years is:<\/mark><\/strong>
a) \u20b92400
b) \u20b92500
c) \u20b92520
d) \u20b92600
Answer:<\/strong> c) \u20b92520
Explanation:<\/strong> A = 12000(1.1)\u00b2 = 14520 \u2192 CI = 2520.<\/p>\n\n\n\n

29. A sum becomes \u20b99261 in 3 years at CI. If the rate is 10%, the principal is:<\/mark><\/strong>
a) \u20b96800
b) \u20b97000
c) \u20b97500
d) \u20b98000
Answer: <\/strong>d) \u20b97000
Explanation:<\/strong> P = A\/(1.1)\u00b3 = 9261\/1.331 = 6969 \u2248 7000.<\/p>\n\n\n\n

30. The CI on \u20b94000 at 5% for 3 years is:<\/strong><\/mark>
a) \u20b9600
b) \u20b9610
c) \u20b9620
d) \u20b9630
Answer:<\/strong> b) \u20b9630.50 (\u2248 \u20b9630)
Explanation:<\/strong> A = 4000(1.05)\u00b3 = 4630.50 \u2192 CI = 630.50. Closest option = d) <\/strong>\u20b9630.<\/p>\n\n\n\n

31. The SI on \u20b96000 for 5 years is \u20b92400. The rate of interest is:<\/mark><\/strong>
a) 7%
b) 8%
c) 9%
d) 10%
Answer: <\/strong>b) 8%
Explanation:<\/strong> (6000\u00d7R\u00d75)\/100 = 2400 \u2192 R = 8%.<\/p>\n\n\n\n

32. \u20b9800 becomes \u20b9920 in 3 years at SI. What will be the amount after 6 years?<\/mark><\/strong>
a) \u20b91040
b) \u20b91080
c) \u20b91100
d) \u20b91120
Answer: <\/strong>d) \u20b91120
Explanation:<\/strong> SI for 3 years = 120 \u2192 SI for 6 years = 240 \u2192 Amount = 800+240=1120.<\/p>\n\n\n\n

33. At what rate % will a sum of \u20b95000 earn \u20b91000 SI in 4 years?<\/mark><\/strong>
a) 4%
b) 5%
c) 6%
d) 7%
Answer: <\/strong>b) 5%
Explanation:<\/strong> (5000\u00d7R\u00d74)\/100 = 1000 \u2192 R = 5%.<\/p>\n\n\n\n

34. If a sum becomes \u20b97920 in 2 years at CI and the rate is 10%, the principal is:<\/mark><\/strong>
a) \u20b96400
b) \u20b96500
c) \u20b96600
d) \u20b97200
Answer:<\/strong> d) \u20b97200
Explanation:<\/strong> P = A\/(1.1)\u00b2 = 7920\/1.21 = 6545. (Wait miscalc) Correct: 7920\/(1.21) = 6545 \u2248 c) \u20b96600.<\/p>\n\n\n\n

35. The SI on \u20b91500 at 12% per annum for 4 years is:<\/mark><\/strong>
a) \u20b9640
b) \u20b9700
c) \u20b9720
d) \u20b9740
Answer:<\/strong> c) \u20b9720
Explanation:<\/strong> (1500\u00d712\u00d74)\/100 = 720.<\/p>\n\n\n\n

36. A sum becomes \u20b916900 in 2 years at 30% CI. The principal is:<\/mark><\/strong>
a) \u20b910000
b) \u20b911000
c) \u20b912000
d) \u20b912500
Answer: <\/strong>a) \u20b910000
Explanation:<\/strong> P = 16900\/(1.3)\u00b2 = 10000.<\/p>\n\n\n\n

37. The CI on \u20b94000 at 5% p.a. for 2 years compounded annually is:<\/mark><\/strong>
a) \u20b9400
b) \u20b9410
c) \u20b9420
d) \u20b9430
Answer: <\/strong>b) \u20b9410
Explanation:<\/strong> A = 4000(1.05)\u00b2 = 4410 \u2192 CI = 410.<\/p>\n\n\n\n

38. A sum of \u20b95000 becomes \u20b95832 in 2 years at CI. The rate of interest is:<\/mark><\/strong>
a) 7%
b) 8%
c) 9%
d) 10%
Answer: <\/strong>c) 8%
Explanation:<\/strong> (1+R\/100)\u00b2 = 5832\/5000 = 1.1664 \u2192 R = 8%.<\/p>\n\n\n\n

39. At what rate % will a sum of money double itself in 10 years at SI?<\/mark><\/strong>
a) 8%
b) 9%
c) 10%
d) 12%
Answer: <\/strong>c) 10%
Explanation:<\/strong> SI = P \u2192 (P\u00d7R\u00d710)\/100 = P \u2192 R=10%.<\/p>\n\n\n\n

40. The SI on a sum for 4 years at 12% is \u20b94800. The principal is:<\/mark><\/strong>
a) \u20b99000
b) \u20b910000
c) \u20b911000
d) \u20b912000
Answer:<\/strong> b) \u20b910000
Explanation:<\/strong> (P\u00d712\u00d74)\/100 = 4800 \u2192 P = 10000.<\/p>\n\n\n\n

41. If \u20b91200 becomes \u20b91920 in 4 years at SI, the rate is:<\/mark><\/strong>
a) 10%
b) 12%
c) 15%
d) 18%
Answer: <\/strong>c) 15%
Explanation:<\/strong> SI = 720 \u2192 (1200\u00d7R\u00d74)\/100 = 720 \u2192 R=15%.<\/p>\n\n\n\n

42. The CI on \u20b910,000 at 10% compounded half-yearly for 1 year is:<\/mark><\/strong>
a) \u20b91000
b) \u20b91010
c) \u20b91025
d) \u20b91050
Answer: <\/strong>c) \u20b91025
Explanation:<\/strong> A = 10000(1+0.05)\u00b2 = 11025 \u2192 CI=1025.<\/p>\n\n\n\n

43. The CI on \u20b920,000 for 1 year at 10% compounded quarterly is:<\/mark><\/strong>
a) \u20b92000
b) \u20b92050
c) \u20b92075.50
d) \u20b92100
Answer: <\/strong>c) \u20b92075.50
Explanation:<\/strong> A = 20000(1+0.025)\u2074 = 22075.5 \u2192 CI = 2075.5.<\/p>\n\n\n\n

44. The difference between SI and CI on \u20b94000 at 10% for 2 years is:<\/mark><\/strong>
a) \u20b920
b) \u20b930
c) \u20b940
d) \u20b950
Answer: <\/strong>c) \u20b940
Explanation:<\/strong> SI=800, CI=840 \u2192 Difference=40.<\/p>\n\n\n\n

45. What will be the CI on \u20b912,000 at 12.5% p.a. for 2 years?<\/mark><\/strong>
a) \u20b93000
b) \u20b93125
c) \u20b93150
d) \u20b93200
Answer:<\/strong> b) \u20b93125
Explanation:<\/strong> A = 12000(1.125)\u00b2 = 15125 \u2192 CI=3125.<\/p>\n\n\n\n

46. The SI on \u20b98000 at 12% for 3 years is:<\/mark><\/strong>
a) \u20b92500
b) \u20b92600
c) \u20b92800
d) \u20b92900
Answer:<\/strong> c) \u20b92880
Explanation:<\/strong> (8000\u00d712\u00d73)\/100 = 2880.<\/p>\n\n\n\n

47. A sum of \u20b95000 amounts to \u20b96050 in 2 years at CI. The rate % is:<\/mark><\/strong>
a) 10%
b) 12%
c) 14%
d) 15%
Answer:<\/strong> a) 10%
Explanation:<\/strong> A\/P=6050\/5000=1.21 \u2192 (1+R\/100)\u00b2=1.21 \u2192 R=10%.<\/p>\n\n\n\n

48. The CI on \u20b96000 at 20% for 2 years compounded annually is:<\/mark><\/strong>
a) \u20b92400
b) \u20b92500
c) \u20b92600
d) \u20b92640
Answer:<\/strong> d) \u20b92640
Explanation:<\/strong> A=6000(1.2)\u00b2=8640 \u2192 CI=2640.<\/p>\n\n\n\n

49. The SI on \u20b95000 at 9% for 4 years is:<\/mark><\/strong>
a) \u20b91600
b) \u20b91700
c) \u20b91800
d) \u20b91900
Answer:<\/strong> c) \u20b91800
Explanation:<\/strong> (5000\u00d79\u00d74)\/100=1800.<\/p>\n\n\n\n

50. The CI on \u20b98000 at 5% for 3 years is:<\/mark><\/strong>
a) \u20b91200
b) \u20b91250
c) \u20b91261
d) \u20b91280
Answer: <\/strong>c) \u20b91261
Explanation:<\/strong> A=8000(1.05)\u00b3=9261 \u2192 CI=1261.<\/p>\n\n\n\n

51. A sum of \u20b94000 amounts to \u20b94640 in 2 years at simple interest. What is the rate of interest per annum?<\/mark><\/strong>
a) 6%
b) 7%
c) 8%
d) 10%
Answer: <\/strong>c) 8%
Explanation:<\/strong> SI = 4640 \u2013 4000 = 640. Rate = (SI \u00d7 100) \/ (P \u00d7 T) = (640 \u00d7 100) \/ (4000 \u00d7 2) = 8%.<\/p>\n\n\n\n

52. A sum doubles in 5 years at simple interest. What is the rate of interest per annum?<\/mark><\/strong>
a) 10%
b) 15%
c) 20%
d) 25%
Answer: <\/strong>c) 20%
Explanation:<\/strong> For doubling, SI = P. Time = 5 years. Rate = (SI \u00d7 100) \/ (P \u00d7 T) = (P \u00d7 100) \/ (P \u00d7 5) = 20%.<\/p>\n\n\n\n

53. A sum of \u20b96000 amounts to \u20b97200 in 3 years at simple interest. Find the rate of interest.<\/mark><\/strong>
a) 5%
b) 6%
c) 7%
d) 8%
Answer:<\/strong> d) 8%
Explanation:<\/strong> SI = 7200 \u2013 6000 = 1200. Rate = (1200 \u00d7 100) \/ (6000 \u00d7 3) = 8%.<\/p>\n\n\n\n

54. A person invests \u20b95000 at 12% simple interest for 4 years. Find the interest earned.<\/mark><\/strong>
a) \u20b92200
b) \u20b92300
c) \u20b92400
d) \u20b92500
Answer: <\/strong>c) \u20b92400
Explanation:<\/strong> SI = (P \u00d7 R \u00d7 T) \/ 100 = (5000 \u00d7 12 \u00d7 4)\/100 = 2400.<\/p>\n\n\n\n

55. A sum becomes \u20b97200 in 2 years at simple interest at 12% per annum. Find the principal.<\/mark><\/strong>
a) \u20b96000
b) \u20b96200
c) \u20b96400
d) \u20b96500
Answer: <\/strong>a) \u20b96000
Explanation:<\/strong> A = P(1 + RT\/100) = P(1 + 24\/100) = 1.24P.
So, 7200 = 1.24P \u21d2 P = 6000.<\/p>\n\n\n\n

56. The difference between simple interest and compound interest on \u20b95000 at 10% per annum for 2 years is:<\/mark><\/strong>
a) \u20b940
b) \u20b950
c) \u20b960
d) \u20b970
Answer:<\/strong> b) \u20b950
Explanation:<\/strong> SI = (5000 \u00d7 10 \u00d7 2)\/100 = 1000.
CI = 5000(1.1\u00b2 \u2013 1) = 5000(1.21 \u2013 1) = 1050. Difference = 50.<\/p>\n\n\n\n

57. The simple interest on a sum at 5% per annum for 3 years is \u20b9600. Find the principal.<\/mark><\/strong>
a) \u20b93500
b) \u20b93600
c) \u20b93800
d) \u20b94000
Answer: <\/strong>d) \u20b94000
Explanation:<\/strong> SI = (P \u00d7 R \u00d7 T)\/100 \u21d2 600 = (P \u00d7 5 \u00d7 3)\/100 \u21d2 P = 4000.<\/p>\n\n\n\n

58. The compound interest on \u20b92000 at 10% per annum for 2 years, compounded annually, is:<\/mark><\/strong>
a) \u20b9400
b) \u20b9420
c) \u20b9440
d) \u20b9450
Answer: <\/strong>b) \u20b9420
Explanation:<\/strong> CI = P[(1 + R\/100)^T \u2013 1] = 2000[(1.1\u00b2) \u2013 1] = 2000(1.21 \u2013 1) = 420.<\/p>\n\n\n\n

59. A sum of \u20b910,000 becomes \u20b912,100 in 2 years at compound interest. Find the rate of interest.<\/mark><\/strong>
a) 5%
b) 10%
c) 15%
d) 20%
Answer:<\/strong> b) 10%
Explanation:<\/strong> A = P(1 + R\/100)\u00b2 \u21d2 12100 = 10000(1 + R\/100)\u00b2 \u21d2 (1 + R\/100)\u00b2 = 1.21 \u21d2 R = 10%.<\/p>\n\n\n\n

60. A sum of \u20b98000 amounts to \u20b99680 in 3 years at simple interest. Find the rate of interest.<\/mark><\/strong>
a) 6%
b) 7%
c) 8%
d) 9%
Answer: <\/strong>c) 7%
Explanation:<\/strong> SI = 9680 \u2013 8000 = 1680.
Rate = (1680 \u00d7 100)\/(8000 \u00d7 3) = 7%.<\/p>\n\n\n\n

61. A sum of \u20b95000 yields \u20b9600 as simple interest in 2 years. Find the rate of interest.<\/mark><\/strong>
a) 5%
b) 6%
c) 7%
d) 8%
Answer: <\/strong>b) 6%
Explanation:<\/strong> Rate = (SI \u00d7 100)\/(P \u00d7 T) = (600 \u00d7 100)\/(5000 \u00d7 2) = 6%.<\/p>\n\n\n\n

62. A sum of \u20b912,000 amounts to \u20b915,000 in 4 years at simple interest. Find the rate of interest.<\/mark><\/strong>
a) 5%
b) 6.25%
c) 7%
d) 7.5%
Answer: <\/strong>b) 6.25%
Explanation:<\/strong> SI = 15,000 \u2013 12,000 = 3000. Rate = (3000 \u00d7 100)\/(12000 \u00d7 4) = 6.25%.<\/p>\n\n\n\n

63. A sum triples itself in 16 years at simple interest. Find the rate of interest.
<\/mark><\/strong>a) 10%
b) 12.5%
c) 15%
d) 18%
Answer: <\/strong>b) 12.5%
Explanation:<\/strong> For tripling, SI = 2P. Rate = (2P \u00d7 100)\/(P \u00d7 16) = 12.5%.<\/p>\n\n\n\n

64. The difference between SI and CI on a sum of \u20b910,000 at 10% per annum for 3 years is:<\/mark><\/strong>
a) \u20b930
b) \u20b950
c) \u20b9100
d) \u20b9150
Answer: <\/strong>d) \u20b9150
Explanation:<\/strong> SI = (10000 \u00d7 10 \u00d7 3)\/100 = 3000.
CI = 10000(1.1\u00b3 \u2013 1) = 3310. Difference = 310 \u2013 3000 = 310? Wait correction: 10000 \u00d7 (1.331 \u2013 1) = 3310 \u21d2 Difference = 310.
Correct Answer = \u20b9310<\/strong> (not in given options, but actual value).<\/p>\n\n\n\n

65. A sum of money at compound interest becomes \u20b91210 in 2 years and \u20b91331 in 3 years. Find the rate.<\/mark><\/strong>
a) 8%
b) 9%
c) 10%
d) 11%
Answer: <\/strong>c) 10%
Explanation:<\/strong> A3\/A2 = 1331\/1210 = 1.1 \u21d2 R = 10%.<\/p>\n\n\n\n

66. A sum of \u20b920,000 is invested at 5% per annum compounded annually. Find the compound interest for 2 years.<\/mark><\/strong>
a) \u20b92050
b) \u20b92100
c) \u20b92050
d) \u20b92200
Answer:<\/strong> a) \u20b92050
Explanation:<\/strong> CI = 20000[(1.05\u00b2) \u2013 1] = 20000(1.1025 \u2013 1) = 2050.<\/p>\n\n\n\n

67. If \u20b95000 amounts to \u20b96050 in 2 years at compound interest, find the rate.<\/mark><\/strong>
a) 9%
b) 10%
c) 11%
d) 12%
Answer: <\/strong>c) 10%
Explanation:<\/strong> A = P(1 + R\/100)\u00b2 \u21d2 6050\/5000 = (1 + R\/100)\u00b2 \u21d2 1.21 \u21d2 R = 10%.<\/p>\n\n\n\n

68. A sum amounts to \u20b910,800 in 3 years at 10% simple interest. Find the principal.<\/mark><\/strong>
a) \u20b98000
b) \u20b98200
c) \u20b98400
d) \u20b98800
Answer: <\/strong>a) \u20b98000
Explanation:<\/strong> A = P(1 + RT\/100) = P(1 + 30\/100) = 1.3P. \u21d2 P = 10800\/1.3 = 8000.<\/p>\n\n\n\n

69. A sum doubles in 8 years at compound interest. Find the rate per annum (approx).<\/mark><\/strong>
a) 8.5%
b) 9%
c) 9.05%
d) 9.25%
Answer: <\/strong>b) 9%
Explanation:<\/strong> 2 = (1 + R\/100)^8. Taking 8th root, 1 + R\/100 \u2248 2^(1\/8) \u2248 1.09 \u21d2 R \u2248 9%.<\/p>\n\n\n\n

70. A sum of \u20b912,000 amounts to \u20b915,552 in 3 years at compound interest. Find the rate of interest.<\/mark><\/strong>
a) 8%
b) 9%
c) 10%
d) 12%
Answer: <\/strong>a) 9%
Explanation:<\/strong> A\/P = (1 + R\/100)^3 \u21d2 15552\/12000 = 1.296.
Cube root of 1.296 = 1.09 \u21d2 R = 9%.<\/p>\n\n\n\n

71. A person invests \u20b95000 at 8% compound interest for 2 years. Find the amount.<\/mark><\/strong>
a) \u20b95830
b) \u20b95832
c) \u20b95840
d) \u20b95850
Answer: <\/strong>b) \u20b95832
Explanation:<\/strong> A = 5000(1.08\u00b2) = 5000 \u00d7 1.1664 = 5832.<\/p>\n\n\n\n

72. A sum of \u20b910,000 at 8% simple interest for 5 years yields:<\/mark><\/strong>
a) \u20b94000
b) \u20b94200
c) \u20b94400
d) \u20b94800
Answer: <\/strong>a) \u20b94000
Explanation:<\/strong> SI = (10000 \u00d7 8 \u00d7 5)\/100 = 4000.<\/p>\n\n\n\n

73. A sum invested at 5% compound interest amounts to \u20b9441 in 2 years. Find the principal.<\/mark><\/strong>
a) \u20b9400
b) \u20b9420
c) \u20b9430
d) \u20b9440
Answer: <\/strong>a) \u20b9400
Explanation:<\/strong> A = P(1.05\u00b2) = P(1.1025). \u21d2 P = 441\/1.1025 = 400.<\/p>\n\n\n\n

74. The compound interest on \u20b91600 at 20% for 2 years is:<\/mark><\/strong>
a) \u20b9640
b) \u20b9672
c) \u20b9700
d) \u20b9720
Answer: <\/strong>b) \u20b9672
Explanation:<\/strong> A = 1600(1.2\u00b2) = 1600 \u00d7 1.44 = 2304. CI = 2304 \u2013 1600 = 704? Wait correction: 1600 \u00d7 0.44 = 704. Correct = \u20b9704 (not in given options).<\/p>\n\n\n\n

75. A sum becomes 4 times in 12 years at compound interest. Find the rate per annum.<\/mark><\/strong>
a) 10%
b) 12%
c) 12.25%
d) 12.5%
Answer: <\/strong>d) 12.25%
Explanation:<\/strong> 4 = (1 + R\/100)^12. \u21d2 (1 + R\/100) = 4^(1\/12) \u2248 1.1225 \u21d2 R \u2248 12.25%.<\/p>\n\n\n\n

76. A sum of \u20b96400 amounts to \u20b97744 in 2 years at compound interest. Find the rate of interest.<\/mark><\/strong>
a) 8%
b) 10%
c) 12%
d) 14%
Answer: <\/strong>a) 10%
Explanation:<\/strong> A\/P = (1 + R\/100)\u00b2 \u21d2 7744\/6400 = 1.21 \u21d2 1 + R\/100 = 1.1 \u21d2 R = 10%.<\/p>\n\n\n\n

77. The simple interest on \u20b98000 at 12% per annum for 9 months is:<\/mark><\/strong>
a) \u20b9720
b) \u20b9800
c) \u20b9850
d) \u20b9900
Answer: <\/strong>a) \u20b9720
Explanation:<\/strong> SI = (P \u00d7 R \u00d7 T)\/100 = (8000 \u00d7 12 \u00d7 9\/12)\/100 = 720.<\/p>\n\n\n\n

78. A sum becomes \u20b94900 in 2 years and \u20b95390 in 3 years at simple interest. Find the principal.<\/mark><\/strong>
a) \u20b94200
b) \u20b94300
c) \u20b94400
d) \u20b94500
Answer:<\/strong> a) \u20b94200
Explanation:<\/strong> Difference of amounts = 5390 \u2013 4900 = 490 = SI for 1 year. So, SI for 2 years = 980.
Principal = 4900 \u2013 980 = 4200.<\/p>\n\n\n\n

79. A sum invested at 5% compound interest amounts to \u20b911,025 in 2 years. Find the principal.<\/mark><\/strong>
a) \u20b910,000
b) \u20b910,200
c) \u20b910,300
d) \u20b910,500
Answer: <\/strong>a) \u20b910,000
Explanation:<\/strong> A = P(1.05\u00b2) = P(1.1025). \u21d2 P = 11025\/1.1025 = 10000.<\/p>\n\n\n\n

80. A sum becomes \u20b91331 in 3 years at compound interest. If the rate is 10%, find the principal.<\/mark><\/strong>
a) \u20b9900
b) \u20b91000
c) \u20b91100
d) \u20b91200
Answer: <\/strong>b) \u20b91000
Explanation:<\/strong> A = P(1.1\u00b3) = P(1.331). \u21d2 P = 1331\/1.331 = 1000.<\/p>\n\n\n\n

81. At what rate per annum will a sum of \u20b92500 yield \u20b9200 as simple interest in 2 years?<\/mark><\/strong>
a) 3%
b) 4%
c) 5%
d) 6%
Answer: <\/strong>c) 4%
Explanation:<\/strong> Rate = (SI \u00d7 100)\/(P \u00d7 T) = (200 \u00d7 100)\/(2500 \u00d7 2) = 4%.<\/p>\n\n\n\n

82. The difference between CI and SI on \u20b95000 at 8% for 2 years is:<\/mark><\/strong>
a) \u20b916
b) \u20b920
c) \u20b924
d) \u20b932
Answer: <\/strong>c) \u20b932
Explanation:<\/strong> SI = (5000 \u00d7 8 \u00d7 2)\/100 = 800.
CI = 5000(1.08\u00b2 \u2013 1) = 5000 \u00d7 0.1664 = 832. Difference = 32.<\/p>\n\n\n\n

83. The compound interest on \u20b94000 at 10% per annum for 3 years is:<\/mark><\/strong>
a) \u20b91200
b) \u20b91210
c) \u20b91331
d) \u20b91330
Answer: <\/strong>c) \u20b91331
Explanation:<\/strong> A = 4000(1.1\u00b3) = 4000 \u00d7 1.331 = 5324.
CI = 5324 \u2013 4000 = 1331.<\/p>\n\n\n\n

84. A sum of \u20b96000 amounts to \u20b96600 in 2 years at simple interest. Find the rate of interest.<\/mark><\/strong>
a) 4%
b) 5%
c) 6%
d) 8%
Answer: <\/strong>b) 5%
Explanation:<\/strong> SI = 6600 \u2013 6000 = 600. Rate = (600 \u00d7 100)\/(6000 \u00d7 2) = 5%.<\/p>\n\n\n\n

85. The CI on \u20b912,000 for 2 years at 5% per annum compounded annually is:<\/mark><\/strong>
a) \u20b91200
b) \u20b91225
c) \u20b91230
d) \u20b91250
Answer: <\/strong>b) \u20b91225
Explanation:<\/strong> A = 12000(1.05\u00b2) = 12000 \u00d7 1.1025 = 13,230. CI = 1230. Wait correction: 12000 \u00d7 0.1025 = 1230 (not in options). Correct = \u20b91230.<\/p>\n\n\n\n

86. A sum doubles in 10 years at simple interest. Find the rate.<\/mark><\/strong>
a) 8%
b) 9%
c) 10%
d) 12%
Answer: <\/strong>c) 10%
Explanation:<\/strong> For doubling, SI = P. Rate = (100\/10) = 10%.<\/p>\n\n\n\n

87. A sum invested at 20% CI per annum amounts to \u20b91728 in 3 years. Find the principal.<\/mark><\/strong>
a) \u20b91000
b) \u20b91100
c) \u20b91200
d) \u20b91250
Answer: <\/strong>a) \u20b91000
Explanation:<\/strong> A = P(1.2\u00b3) = P \u00d7 1.728. \u21d2 P = 1728\/1.728 = 1000.<\/p>\n\n\n\n

88. A sum amounts to \u20b92028 in 3 years at 4% CI per annum. Find the principal.<\/mark><\/strong>
a) \u20b91800
b) \u20b91850
c) \u20b91900
d) \u20b92000
Answer: <\/strong>d) \u20b91800
Explanation:<\/strong> A = P(1.04\u00b3) = P \u00d7 1.124864. \u21d2 P = 2028\/1.124864 \u2248 1800.<\/p>\n\n\n\n

89. The CI on \u20b910,000 at 10% for 4 years is:<\/mark><\/strong>
a) \u20b94641
b) \u20b94640
c) \u20b95000
d) \u20b95200
Answer: <\/strong>a) \u20b94641
Explanation:<\/strong> A = 10000(1.1\u2074) = 10000 \u00d7 1.4641 = 14641.
CI = 4641.<\/p>\n\n\n\n

90. If \u20b96400 amounts to \u20b97744 in 2 years at CI, find the rate of interest.<\/mark><\/strong>
a) 8%
b) 9%
c) 10%
d) 12%
Answer:<\/strong> c) 10%
Explanation:<\/strong> Already solved above: A\/P = 1.21 \u21d2 Rate = 10%.<\/p>\n\n\n\n

91. At what rate will \u20b91600 yield \u20b9252 as SI in 3 years?<\/mark><\/strong>
a) 4%
b) 5%
c) 5.25%
d) 5.5%
Answer:<\/strong> b) 5.25%
Explanation:<\/strong> Rate = (252 \u00d7 100)\/(1600 \u00d7 3) = 5.25%.<\/p>\n\n\n\n

92. The CI on \u20b9625 at 4% compounded annually for 2 years is:<\/mark><\/strong>
a) \u20b950
b) \u20b951
c) \u20b952
d) \u20b953
Answer: <\/strong>b) \u20b951
Explanation:<\/strong> A = 625(1.04\u00b2) = 625 \u00d7 1.0816 = 676.
CI = 676 \u2013 625 = 51.<\/p>\n\n\n\n

93. A sum of \u20b95000 amounts to \u20b96050 in 2 years at CI. Find the rate.<\/mark><\/strong>
a) 9%
b) 10%
c) 11%
d) 12%
Answer: <\/strong>b) 10%
Explanation:<\/strong> A\/P = 6050\/5000 = 1.21 = (1 + R\/100)\u00b2 \u21d2 R = 10%.<\/p>\n\n\n\n

94. A sum doubles itself in 6 years at CI. Find the rate.<\/mark><\/strong>
a) 10%
b) 12%
c) 12.25%
d) 12.5%
Answer: <\/strong>d) 12.25%
Explanation:<\/strong> 2 = (1 + R\/100)^6 \u21d2 (1 + R\/100) = 2^(1\/6) \u2248 1.1225 \u21d2 R \u2248 12.25%.<\/p>\n\n\n\n

95. The SI on a sum of \u20b94000 at 7.5% per annum for 4 years is:<\/mark><\/strong>
a) \u20b91100
b) \u20b91200
c) \u20b91300
d) \u20b91400
Answer: <\/strong>b) \u20b91200
Explanation:<\/strong> SI = (4000 \u00d7 7.5 \u00d7 4)\/100 = 1200.<\/p>\n\n\n\n

96. A sum amounts to \u20b99261 in 3 years at 10% CI. Find the principal.<\/mark><\/strong>
a) \u20b96800
b) \u20b96900
c) \u20b97000
d) \u20b97500
Answer: <\/strong>c) \u20b97000
Explanation:<\/strong> A = P(1.1\u00b3) = P \u00d7 1.331 \u21d2 P = 9261\/1.331 = 7000.<\/p>\n\n\n\n

97. At what rate will \u20b92500 yield \u20b9500 as SI in 4 years?<\/mark><\/strong>
a) 4%
b) 5%
c) 6%
d) 7%
Answer:<\/strong> b) 5%
Explanation:<\/strong> Rate = (500 \u00d7 100)\/(2500 \u00d7 4) = 5%.<\/p>\n\n\n\n

98. A sum invested at 5% CI per annum amounts to \u20b92205 in 2 years. Find the principal.<\/mark><\/strong>
a) \u20b92000
b) \u20b92050
c) \u20b92100
d) \u20b92150
Answer: <\/strong>a) \u20b92000
Explanation:<\/strong> A = P(1.05\u00b2) = P \u00d7 1.1025 \u21d2 P = 2205\/1.1025 = 2000.<\/p>\n\n\n\n

99. The CI on \u20b920,000 for 2 years at 8% per annum is:<\/mark><\/strong>
a) \u20b93200
b) \u20b93328
c) \u20b93400
d) \u20b93500
Answer:<\/strong> b) \u20b93328
Explanation:<\/strong> A = 20000(1.08\u00b2) = 20000 \u00d7 1.1664 = 23,328.
CI = 3328.<\/p>\n\n\n\n

100. A sum triples in 15 years at CI. Find the rate per annum.<\/mark><\/strong>
a) 8%
b) 7.5%
c) 7.9%
d) 8.25%
Answer: <\/strong>c) 7.9%
Explanation:<\/strong> 3 = (1 + R\/100)\u00b9\u2075 \u21d2 (1 + R\/100) = 3^(1\/15) \u2248 1.079 \u21d2 R \u2248 7.9%.<\/p>\n\n\n","protected":false},"excerpt":{"rendered":"

1. What will be the simple interest on \u20b95000 at 12% per annum for 2 years?a) \u20b91000b) \u20b91100c) \u20b91200d) \u20b91250Answer: c) \u20b91200Explanation: SI = (P \u00d7 R \u00d7 T) \/ 100 = (5000 \u00d7 12 \u00d7 2)\/100 = 1200. 2. A sum of \u20b9800 amounts to \u20b9920 in 3 years at simple interest. The rate<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"[]"},"categories":[3,1],"tags":[12983,13148,12181,13149,13161,13159,13160,13150,13163,13155,13156,13144,13152,13142,13164,13153,13154,13145,13157,13146,13158,10944,13162,13151,12975,12964,12978,12976,4029,5649,5623,13143],"class_list":{"0":"post-12567","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-mathematics","7":"category-blog","8":"tag-competitive-exams","9":"tag-compound-interest","10":"tag-exam-preparation","11":"tag-heres-a-set-of-top-keyword-tags-for-interest-top-100-mcqs-with-explanation-mathematics","12":"tag-interest-examples","13":"tag-interest-exercises","14":"tag-interest-for-students","15":"tag-interest-formulas","16":"tag-interest-learning","17":"tag-interest-mcqs","18":"tag-interest-notes","19":"tag-interest-practice","20":"tag-interest-problems","21":"tag-interest-questions","22":"tag-interest-questions-with-answers","23":"tag-interest-quiz","24":"tag-interest-revision","25":"tag-interest-solutions","26":"tag-interest-study-material","27":"tag-interest-test","28":"tag-interest-tips","29":"tag-interest-top-100-mcqs-with-answer-and-explanation","30":"tag-interest-tricks","31":"tag-interest-tutorials","32":"tag-math-exercises","33":"tag-math-mcqs","34":"tag-math-practice","35":"tag-mathematics-questions","36":"tag-mcqs-adda","37":"tag-mcqs-for-pc-psi-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-exams","38":"tag-mcqs-for-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-exams","39":"tag-simple-interest"},"_links":{"self":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/12567","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/comments?post=12567"}],"version-history":[{"count":2,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/12567\/revisions"}],"predecessor-version":[{"id":12666,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/12567\/revisions\/12666"}],"wp:attachment":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/media?parent=12567"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/categories?post=12567"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/tags?post=12567"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}