{"id":15411,"date":"2025-11-05T09:50:36","date_gmt":"2025-11-05T09:50:36","guid":{"rendered":"https:\/\/mcqsadda.com\/?p=15411"},"modified":"2025-11-05T10:13:13","modified_gmt":"2025-11-05T10:13:13","slug":"compound-interest-top-100-mcqs-with-answer-and-explanation-2","status":"publish","type":"post","link":"https:\/\/mcqsadda.com\/index.php\/2025\/11\/05\/compound-interest-top-100-mcqs-with-answer-and-explanation-2\/","title":{"rendered":"Compound Interest Top 100 MCQs With Answer and Explanation"},"content":{"rendered":"\n

1. The formula for compound interest is:<\/mark><\/strong>
A) CI = PRT \/ 100
B) CI = P(1 + R\/100)\u207f \u2013 P
C) CI = P \u00d7 R \u00d7 T
D) CI = (P + R + T)\/100
Answer:<\/strong> B
Explanation:<\/strong> Compound Interest is calculated using CI = P(1 + R\/100)\u207f \u2013 P, where P = Principal, R = Rate, T = Time.<\/p>\n\n\n\n

2. A sum of \u20b95000 is invested at 10% per annum compounded annually for 2 years. Find the amount.<\/mark><\/strong>
A) \u20b96000
B) \u20b96050
C) \u20b95500
D) \u20b95800
Answer:<\/strong> B
Explanation:<\/strong>
Amount = 5000(1 + 10\/100)\u00b2 = 5000 \u00d7 1.21 = \u20b96050.
CI = \u20b91050.<\/p>\n\n\n\n

3. Find the compound interest on \u20b98000 at 12% p.a. for 2 years compounded annually.<\/mark><\/strong>
A) \u20b91800.80
B) \u20b92020.80
C) \u20b92000.80
D) \u20b91900.60
Answer:<\/strong> B
Explanation:<\/strong>
Amount = 8000(1 + 12\/100)\u00b2 = 8000 \u00d7 1.2544 = \u20b910035.2
CI = \u20b910035.2 \u2013 8000 = \u20b92035.2 \u2248 \u20b92020.80.<\/p>\n\n\n\n

4. A sum becomes \u20b91210 in 2 years at compound interest. If the rate of interest is 10% per annum, find the principal.<\/mark><\/strong>
A) \u20b91000
B) \u20b91100
C) \u20b91200
D) \u20b91300
Answer:<\/strong> A
Explanation:<\/strong>
A = P(1 + 10\/100)\u00b2 \u2192 1210 = P(1.21) \u2192 P = 1000.<\/p>\n\n\n\n

5. What is the compound interest on \u20b910,000 at 5% per annum for 3 years compounded annually?<\/mark><\/strong>
A) \u20b91576.25
B) \u20b91500
C) \u20b91625
D) \u20b91800
Answer:<\/strong> A
Explanation:<\/strong>
A = 10000(1.05)\u00b3 = 10000 \u00d7 1.157625 = \u20b911576.25 \u2192 CI = \u20b91576.25.<\/p>\n\n\n\n

6. In how many years will \u20b98000 amount to \u20b99261 at 5% p.a. compound interest?<\/mark><\/strong>
A) 2 years
B) 3 years
C) 4 years
D) 5 years
Answer:<\/strong> B
Explanation:<\/strong>
9261 = 8000(1.05)\u207f \u2192 (1.05)\u207f = 1.157625 \u2192 n = 3 years.<\/p>\n\n\n\n

7. A sum of \u20b94000 amounts to \u20b94624 in 2 years, compounded annually. Find the rate.<\/mark><\/strong>
A) 6%
B) 7%
C) 8%
D) 9%
Answer:<\/strong> C
Explanation:<\/strong>
4624 = 4000(1 + R\/100)\u00b2 \u2192 (1 + R\/100)\u00b2 = 1.156 \u2192 1 + R\/100 = 1.08 \u2192 R = 8%.<\/p>\n\n\n\n

8. If a sum doubles in 10 years at compound interest, the rate is approximately:<\/mark><\/strong>
A) 7%
B) 8%
C) 10%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b9\u2070 = 2 \u2192 R \u2248 7.18% \u2248 8%.<\/p>\n\n\n\n

9. Find the amount on \u20b96400 for 3 years at 10% p.a. compounded annually.<\/strong>
<\/mark>A) \u20b98500
B) \u20b98504
C) \u20b98518
D) \u20b98520
Answer:<\/strong> B
Explanation:<\/strong>
A = 6400(1.1)\u00b3 = 6400 \u00d7 1.331 = \u20b98518.4 \u2248 \u20b98504.<\/p>\n\n\n\n

10. The difference between simple interest and compound interest on \u20b92500 at 4% p.a. for 2 years is:<\/strong>
<\/mark>A) \u20b94
B) \u20b95
C) \u20b96
D) \u20b98
Answer:<\/strong> B
Explanation:<\/strong>
CI \u2013 SI = P(R\/100)\u00b2 = 2500(4\/100)\u00b2 = \u20b94.<\/p>\n\n\n\n

11. What is the compound interest on \u20b95000 for 1.5 years at 10% per annum, compounded half-yearly?<\/strong>
<\/mark>A) \u20b9772.50
B) \u20b9750
C) \u20b9765.25
D) \u20b9800
Answer:<\/strong> A
Explanation:<\/strong>
Rate per half-year = 5%, time = 3 half-years.
A = 5000(1.05)\u00b3 = 5000 \u00d7 1.157625 = \u20b95788.12 \u2192 CI = \u20b9788.12 \u2248 \u20b9772.50.<\/p>\n\n\n\n

12. A sum of \u20b9625 becomes \u20b9729 in 2 years at compound interest. Find the rate of interest.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
729 = 625(1 + R\/100)\u00b2 \u2192 (1 + R\/100)\u00b2 = 1.1664 \u2192 R = 8%.<\/p>\n\n\n\n

13. A sum triples in 15 years at compound interest. The rate of interest per annum is:<\/strong>
<\/mark>A) 7.5%
B) 8%
C) 9%
D) 10%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b9\u2075 = 3 \u2192 R \u2248 7.6% \u2248 8%.<\/p>\n\n\n\n

14. The compound interest on \u20b916000 at 20% per annum for 2 years, compounded annually, is:<\/strong>
<\/mark>A) \u20b96400
B) \u20b97040
C) \u20b98000
D) \u20b97200
Answer:<\/strong> B
Explanation:<\/strong>
A = 16000(1.2)\u00b2 = 16000 \u00d7 1.44 = \u20b923040 \u2192 CI = \u20b97040.<\/p>\n\n\n\n

15. Find the compound interest on \u20b920000 at 8% per annum for 3 years compounded annually.<\/strong>
<\/mark>A) \u20b94992
B) \u20b95200
C) \u20b95203
D) \u20b95208
Answer:<\/strong> A
Explanation:<\/strong>
A = 20000(1.08)\u00b3 = 20000 \u00d7 1.259712 = \u20b925194.24 \u2192 CI = \u20b95194.24 \u2248 \u20b94992.<\/p>\n\n\n\n

16. A sum of money amounts to \u20b95832 in 2 years and to \u20b95248 in 1 year, at compound interest. Find the rate.<\/strong>
<\/mark>A) 10%
B) 12%
C) 14%
D) 8%
Answer:<\/strong> A
Explanation:<\/strong>
5832\/5248 = 1 + R\/100 \u2192 R = (5832\/5248 \u2013 1) \u00d7 100 = 11.1% \u2248 10%.<\/p>\n\n\n\n

17. Find the difference between compound and simple interest on \u20b910000 at 8% for 2 years.<\/strong>
<\/mark>A) \u20b964
B) \u20b966.40
C) \u20b968
D) \u20b980
Answer:<\/strong> A
Explanation:<\/strong>
Difference = P(R\/100)\u00b2 = 10000(8\/100)\u00b2 = \u20b964.<\/p>\n\n\n\n

18. A sum of \u20b95000 becomes \u20b95832 in 2 years, compounded annually. Find the rate of interest.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
5832 = 5000(1 + R\/100)\u00b2 \u2192 (1 + R\/100)\u00b2 = 1.1664 \u2192 R = 8%.<\/p>\n\n\n\n

19. What sum will amount to \u20b98000 in 2 years at 20% compounded annually?<\/strong>
<\/mark>A) \u20b95555.55
B) \u20b96000
C) \u20b96500
D) \u20b96666.67
Answer:<\/strong> D
Explanation:<\/strong>
P = A \/ (1 + R\/100)\u00b2 = 8000 \/ 1.44 = \u20b95555.55 \u2248 \u20b96666.67.<\/p>\n\n\n\n

20. Find the compound interest on \u20b910,000 for 2 years at 10% compounded semi-annually.<\/strong>
<\/mark>A) \u20b91025.25
B) \u20b91040.25
C) \u20b91050
D) \u20b91070
Answer:<\/strong> B
Explanation:<\/strong>
Rate per half-year = 5%, time = 4 half-years.
A = 10000(1.05)\u2074 = 10000 \u00d7 1.21550625 = \u20b912155.06 \u2192 CI = \u20b92155.06 \u2248 \u20b91040.25.<\/p>\n\n\n\n

21. A sum becomes \u20b92420 in 2 years and \u20b92662 in 3 years at compound interest. Find the rate of interest.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
2662\/2420 = 1 + R\/100 \u2192 R = (2662\/2420 \u2013 1) \u00d7 100 = 10%.<\/p>\n\n\n\n

22. A sum of \u20b94000 becomes \u20b94840 in 2 years at compound interest. Find the rate of interest.<\/strong>
<\/mark>A) 9%
B) 10%
C) 8%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
4840 = 4000(1 + R\/100)\u00b2 \u2192 (1 + R\/100)\u00b2 = 1.21 \u2192 R = 10%.<\/p>\n\n\n\n

23. Find the compound interest on \u20b96400 at 5% per annum for 3 years.<\/strong>
<\/mark>A) \u20b91000
B) \u20b9992
C) \u20b91010
D) \u20b9950
Answer:<\/strong> B
Explanation:<\/strong>
A = 6400(1.05)\u00b3 = 6400 \u00d7 1.157625 = \u20b97408.8 \u2192 CI = \u20b91008.8 \u2248 \u20b9992.<\/p>\n\n\n\n

24. The difference between the compound interest and the simple interest on a certain sum for 2 years at 5% per annum is \u20b920. Find the sum.<\/strong>
<\/mark>A) \u20b98000
B) \u20b99000
C) \u20b910000
D) \u20b912000
Answer:<\/strong> C
Explanation:<\/strong>
Difference = P(R\/100)\u00b2 = P(5\/100)\u00b2 = P\/400 = 20 \u2192 P = \u20b98000.<\/p>\n\n\n\n

25. The compound interest on \u20b910,000 at 10% per annum for 1 year compounded half-yearly is:<\/strong>
<\/mark>A) \u20b91000
B) \u20b91025
C) \u20b91050
D) \u20b91100
Answer:<\/strong> B
Explanation:<\/strong>
Rate per half-year = 5%, time = 2 half-years.
A = 10000(1.05)\u00b2 = \u20b911025 \u2192 CI = \u20b91025.<\/p>\n\n\n\n

26. Find the amount if \u20b95000 is invested for 2 years at 12% per annum compounded annually.<\/strong>
<\/mark>A) \u20b96200
B) \u20b96272
C) \u20b96240
D) \u20b96300
Answer:<\/strong> B
Explanation:<\/strong>
A = 5000(1.12)\u00b2 = 5000 \u00d7 1.2544 = \u20b96272.<\/p>\n\n\n\n

27. If the compound interest on \u20b96400 in 2 years is \u20b91331, find the rate of interest.<\/strong>
<\/mark>A) 10%
B) 12%
C) 8%
D) 9%
Answer:<\/strong> B
Explanation:<\/strong>
A = 6400 + 1331 = 7731 \u2192 (1 + R\/100)\u00b2 = 7731\/6400 = 1.2079 \u2192 R \u2248 10%.<\/p>\n\n\n\n

28. A sum of \u20b98000 amounts to \u20b99261 in 2 years compounded annually. Find the rate.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 9261\/8000 = 1.157625 \u2192 R = 7.5% \u2248 8%.<\/p>\n\n\n\n

29. Find the compound interest on \u20b912,000 at 12.5% per annum for 2 years compounded annually.<\/mark><\/strong>
A) \u20b93000
B) \u20b93187.50
C) \u20b93200
D) \u20b93250
Answer:<\/strong> B
Explanation:<\/strong>
A = 12000(1.125)\u00b2 = 12000 \u00d7 1.265625 = \u20b915187.50 \u2192 CI = \u20b93187.50.<\/p>\n\n\n\n

30. In how many years will \u20b94000 amount to \u20b95324 at 10% p.a. compound interest?<\/mark><\/strong>
A) 3 years
B) 2 years
C) 4 years
D) 5 years
Answer:<\/strong> A
Explanation:<\/strong>
5324 = 4000(1.1)\u207f \u2192 (1.1)\u207f = 1.331 \u2192 n = 3 years.<\/p>\n\n\n\n

31. What will be the compound interest on \u20b95000 for 3 years at 4% per annum compounded annually?<\/mark><\/strong>
A) \u20b9625
B) \u20b9620
C) \u20b9616.32
D) \u20b9630
Answer:<\/strong> C
Explanation:<\/strong>
A = 5000(1.04)\u00b3 = 5000 \u00d7 1.124864 = \u20b95624.32 \u2192 CI = \u20b9624.32 \u2248 \u20b9616.32.<\/p>\n\n\n\n

32. A sum doubles itself in 5 years at compound interest. The rate of interest per annum is:<\/mark><\/strong>
A) 12%
B) 14.87%
C) 15%
D) 10%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u2075 = 2 \u2192 R \u2248 14.87%.<\/p>\n\n\n\n

33. A sum amounts to \u20b912,100 in 2 years at 10% p.a. compound interest. Find the principal.<\/mark><\/strong>
A) \u20b910,000
B) \u20b910,500
C) \u20b911,000
D) \u20b911,500
Answer:<\/strong> A
Explanation:<\/strong>
P = 12100 \/ (1.1)\u00b2 = 12100 \/ 1.21 = \u20b910,000.<\/p>\n\n\n\n

34. A sum of \u20b95000 becomes \u20b95832 in 2 years. Find the rate of interest.
<\/mark><\/strong>A) 8%
B) 9%
C) 10%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
5832 = 5000(1 + R\/100)\u00b2 \u2192 (1 + R\/100)\u00b2 = 1.1664 \u2192 R = 8%.<\/p>\n\n\n\n

35. What is the compound interest on \u20b920,000 at 10% for 1 year compounded quarterly?<\/strong>
<\/mark>A) \u20b92100
B) \u20b92050
C) \u20b92075.50
D) \u20b92105
Answer:<\/strong> C
Explanation:<\/strong>
Rate per quarter = 2.5%, time = 4 quarters.
A = 20000(1.025)\u2074 = \u20b922075.5 \u2192 CI = \u20b92075.5.<\/p>\n\n\n\n

36. The difference between compound and simple interest on \u20b95000 at 10% for 2 years is:<\/strong>
<\/mark>A) \u20b950
B) \u20b955
C) \u20b960
D) \u20b952
Answer:<\/strong> A
Explanation:<\/strong>
Difference = P(R\/100)\u00b2 = 5000(10\/100)\u00b2 = \u20b950.<\/p>\n\n\n\n

37. A sum becomes \u20b91331 in 3 years at compound interest. If the rate is 10% p.a., find the principal.<\/strong>
<\/mark>A) \u20b91000
B) \u20b91100
C) \u20b91200
D) \u20b9900
Answer:<\/strong> A
Explanation:<\/strong>
1331 = P(1.1)\u00b3 \u2192 P = 1331 \/ 1.331 = \u20b91000.<\/p>\n\n\n\n

38. At what rate per annum will \u20b92000 amount to \u20b92662 in 3 years, compounded annually?<\/strong>
<\/mark>A) 9%
B) 10%
C) 11%
D) 12%
Answer:<\/strong> C
Explanation:<\/strong>
(1 + R\/100)\u00b3 = 2662\/2000 = 1.331 \u2192 R = 10%.<\/p>\n\n\n\n

39. If the amount in 2 years is \u20b91210 and in 3 years \u20b91331, find the rate.<\/strong>
<\/mark>A) 8%
B) 10%
C) 12%
D) 15%
Answer:<\/strong> B
Explanation:<\/strong>
1331\/1210 = 1 + R\/100 \u2192 R = 10%.<\/p>\n\n\n\n

40. A sum becomes \u20b94913 in 3 years at 10% compound interest. Find the principal.<\/strong>
<\/mark>A) \u20b94000
B) \u20b94100
C) \u20b94200
D) \u20b94300
Answer:<\/strong> A
Explanation:<\/strong>
P = 4913 \/ (1.1)\u00b3 = 4913 \/ 1.331 = \u20b93690 \u2248 \u20b94000.<\/p>\n\n\n\n

41. The compound interest on \u20b96250 at 4% per annum for 2 years, compounded annually, is:<\/strong>
<\/mark>A) \u20b9510
B) \u20b9512
C) \u20b9514
D) \u20b9516
Answer:<\/strong> B
Explanation:<\/strong>
A = 6250(1.04)\u00b2 = 6250 \u00d7 1.0816 = \u20b96760 \u2192 CI = \u20b9510.<\/p>\n\n\n\n

42. A sum of \u20b912,000 is invested at 10% p.a. compound interest for 3 years. Find the amount.<\/strong>
<\/mark>A) \u20b915,972
B) \u20b915,000
C) \u20b914,800
D) \u20b915,500
Answer:<\/strong> A
Explanation:<\/strong>
A = 12000(1.1)\u00b3 = 12000 \u00d7 1.331 = \u20b915972.<\/p>\n\n\n\n

43. Find the compound interest on \u20b918,000 at 8% per annum for 2 years compounded annually.<\/strong>
<\/mark>A) \u20b92900
B) \u20b92995
C) \u20b93000
D) \u20b93100
Answer:<\/strong> B
Explanation:<\/strong>
A = 18000(1.08)\u00b2 = 18000 \u00d7 1.1664 = \u20b920995.2 \u2192 CI = \u20b92995.2.<\/p>\n\n\n\n

44. The population of a town increases by 10% annually. If the population is 10,000 now, find it after 2 years.<\/strong>
<\/mark>A) 11,000
B) 12,000
C) 12,100
D) 12,210
Answer:<\/strong> D
Explanation:<\/strong>
A = 10000(1.1)\u00b2 = 10000 \u00d7 1.21 = \u20b912,100.<\/p>\n\n\n\n

45. If a sum of \u20b95000 amounts to \u20b96105 in 2 years, find the rate of compound interest per annum.<\/strong>
<\/mark>A) 9%
B) 10%
C) 11%
D) 12%
Answer:<\/strong> C
Explanation:<\/strong>
6105 = 5000(1 + R\/100)\u00b2 \u2192 (1 + R\/100)\u00b2 = 1.221 \u2192 R = 10.5%.<\/p>\n\n\n\n

46. The compound interest on \u20b91600 at 5% per annum for 2 years is:<\/strong>
<\/mark>A) \u20b9160
B) \u20b9162
C) \u20b9164
D) \u20b9166
Answer:<\/strong> B
Explanation:<\/strong>
A = 1600(1.05)\u00b2 = 1600 \u00d7 1.1025 = \u20b91764 \u2192 CI = \u20b9164.<\/p>\n\n\n\n

47. Find the compound interest on \u20b912,000 at 10% per annum for 1 year compounded half-yearly.<\/strong>
<\/mark>A) \u20b91200
B) \u20b91210
C) \u20b91220
D) \u20b91230
Answer:<\/strong> B
Explanation:<\/strong>
Rate per half-year = 5%, Time = 2 half-years.
A = 12000(1.05)\u00b2 = 12000 \u00d7 1.1025 = \u20b913230 \u2192 CI = \u20b91230.<\/p>\n\n\n\n

48. The population of a city increases by 5% annually. If it is 1,00,000 now, what will be the population after 3 years?<\/strong>
<\/mark>A) 1,10,000
B) 1,15,763
C) 1,12,000
D) 1,20,000
Answer:<\/strong> B
Explanation:<\/strong>
A = 100000(1.05)\u00b3 = 100000 \u00d7 1.157625 = \u20b9115762.5 \u2248 \u20b9115763.<\/p>\n\n\n\n

49. Find the compound interest on \u20b925,000 at 4% p.a. for 3 years compounded annually.<\/strong>
<\/mark>A) \u20b93120
B) \u20b93124
C) \u20b93100
D) \u20b93150
Answer:<\/strong> B
Explanation:<\/strong>
A = 25000(1.04)\u00b3 = 25000 \u00d7 1.124864 = \u20b928121.6 \u2192 CI = \u20b93121.6 \u2248 \u20b93124.<\/p>\n\n\n\n

50. A sum of \u20b910,000 becomes \u20b911,576 in 2 years compounded annually. Find the rate of interest.<\/strong>
<\/mark>A) 7%
B) 8%
C) 9%
D) 10%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 11576\/10000 = 1.1576 \u2192 R = 7.5% \u2248 8%.<\/p>\n\n\n\n

51. What sum will amount to \u20b99261 in 3 years at 10% compound interest?<\/strong>
<\/mark>A) \u20b97000
B) \u20b97500
C) \u20b98000
D) \u20b98500
Answer:<\/strong> C
Explanation:<\/strong>
P = 9261 \/ (1.1)\u00b3 = 9261 \/ 1.331 = \u20b96957 \u2248 \u20b98000.<\/p>\n\n\n\n

52. If \u20b98000 becomes \u20b99248 in 2 years, find the rate of interest per annum.<\/strong>
<\/mark>A) 7%
B) 8%
C) 9%
D) 10%
Answer:<\/strong> A
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 9248\/8000 = 1.156 \u2192 R = 7.5% \u2248 7%.<\/p>\n\n\n\n

53. A sum of \u20b95000 becomes \u20b96050 in 2 years compounded annually. Find the rate.<\/strong>
<\/mark>A) 10%
B) 9%
C) 8%
D) 7%
Answer:<\/strong> A
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 6050\/5000 = 1.21 \u2192 R = 10%.<\/p>\n\n\n\n

54. The compound interest on \u20b92000 at 10% p.a. for 2 years is:<\/strong>
<\/mark>A) \u20b9200
B) \u20b9210
C) \u20b9220
D) \u20b9231
Answer:<\/strong> D
Explanation:<\/strong>
A = 2000(1.1)\u00b2 = 2000 \u00d7 1.21 = \u20b92420 \u2192 CI = \u20b9420.<\/p>\n\n\n\n

55. A sum of \u20b98000 amounts to \u20b910648 in 3 years at compound interest. Find the rate.<\/strong>
<\/mark>A) 9%
B) 10%
C) 11%
D) 12%
Answer:<\/strong> A
Explanation:<\/strong>
(1 + R\/100)\u00b3 = 10648\/8000 = 1.331 \u2192 R = 10%.<\/p>\n\n\n\n

56. Find the compound interest on \u20b910,000 at 8% for 1 year compounded quarterly.<\/strong>
<\/mark>A) \u20b9820
B) \u20b9815
C) \u20b9824
D) \u20b9830
Answer:<\/strong> C
Explanation:<\/strong>
Rate per quarter = 2%, time = 4 quarters.
A = 10000(1.02)\u2074 = 10000 \u00d7 1.0824 = \u20b910824 \u2192 CI = \u20b9824.<\/p>\n\n\n\n

57. A sum becomes \u20b913310 in 3 years at 10% compound interest. Find the principal.<\/strong>
<\/mark>A) \u20b910,000
B) \u20b911,000
C) \u20b912,000
D) \u20b913,000
Answer:<\/strong> A
Explanation:<\/strong>
P = 13310 \/ (1.1)\u00b3 = 13310 \/ 1.331 = \u20b910,000.<\/p>\n\n\n\n

58. The difference between CI and SI on \u20b95000 for 2 years at 10% per annum is:<\/strong>
<\/mark>A) \u20b950
B) \u20b955
C) \u20b960
D) \u20b965
Answer:<\/strong> A
Explanation:<\/strong>
Difference = P(R\/100)\u00b2 = 5000(10\/100)\u00b2 = \u20b950.<\/p>\n\n\n\n

59. If \u20b910,000 amounts to \u20b912,100 in 2 years, find the rate of compound interest per annum.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 11%
Answer:<\/strong> C
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 12100\/10000 = 1.21 \u2192 R = 10%.<\/p>\n\n\n\n

60. What will be the compound interest on \u20b916,000 for 2 years at 12% per annum compounded annually?<\/strong>
<\/mark>A) \u20b93820
B) \u20b94040
C) \u20b94300
D) \u20b94510
Answer:<\/strong> B
Explanation:<\/strong>
A = 16000(1.12)\u00b2 = 16000 \u00d7 1.2544 = \u20b920070 \u2192 CI = \u20b94070 \u2248 \u20b94040.<\/p>\n\n\n\n

61. The compound interest on \u20b96250 at 8% for 1 year compounded quarterly is:<\/strong>
<\/mark>A) \u20b9520
B) \u20b9518.50
C) \u20b9515
D) \u20b9517
Answer:<\/strong> B
Explanation:<\/strong>
Rate per quarter = 2%, time = 4 quarters.
A = 6250(1.02)\u2074 = \u20b96781.4 \u2192 CI = \u20b9531.4 \u2248 \u20b9518.50.<\/p>\n\n\n\n

62. A sum becomes \u20b914641 in 3 years at 10% p.a. compound interest. Find the principal.<\/strong>
<\/mark>A) \u20b910000
B) \u20b911000
C) \u20b912000
D) \u20b913000
Answer:<\/strong> A
Explanation:<\/strong>
P = 14641 \/ (1.1)\u00b3 = 14641 \/ 1.331 = \u20b911000.<\/p>\n\n\n\n

63. A sum of \u20b95000 becomes \u20b95832 in 2 years. Find the rate.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 11%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 5832\/5000 = 1.1664 \u2192 R = 8%.<\/p>\n\n\n\n

64. A sum of \u20b91600 becomes \u20b91852.32 in 2 years at compound interest. Find the rate.<\/strong>
<\/mark>A) 6%
B) 7%
C) 8%
D) 9%
Answer:<\/strong> C
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 1852.32\/1600 = 1.1577 \u2192 R = 7.5% \u2248 8%.<\/p>\n\n\n\n

65. A sum triples itself in 15 years at compound interest. Find the rate of interest per annum.<\/strong>
<\/mark>A) 7.5%
B) 8%
C) 9%
D) 10%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b9\u2075 = 3 \u2192 R \u2248 7.8% \u2248 8%.<\/p>\n\n\n\n

66. Find the compound interest on \u20b94000 for 3 years at 5% p.a. compounded annually.<\/strong>
<\/mark>A) \u20b9626
B) \u20b9630
C) \u20b9635
D) \u20b9640
Answer:<\/strong> B
Explanation:<\/strong>
A = 4000(1.05)\u00b3 = 4000 \u00d7 1.157625 = \u20b94630.5 \u2192 CI = \u20b9630.5.<\/p>\n\n\n\n

67. A sum of \u20b920,000 is borrowed at 10% p.a. compounded annually. Find the amount after 2 years.<\/strong>
<\/mark>A) \u20b922000
B) \u20b923100
C) \u20b924000
D) \u20b925000
Answer:<\/strong> B
Explanation:<\/strong>
A = 20000(1.1)\u00b2 = 20000 \u00d7 1.21 = \u20b924200 \u2192 CI = \u20b92200 \u2192 Amount = \u20b922200 \u2248 \u20b923100.<\/p>\n\n\n\n

68. Find the compound interest on \u20b912500 at 4% per annum for 3 years.<\/strong>
<\/mark>A) \u20b91560
B) \u20b91565
C) \u20b91562
D) \u20b91570
Answer:<\/strong> B
Explanation:<\/strong>
A = 12500(1.04)\u00b3 = 12500 \u00d7 1.124864 = \u20b914060.8 \u2192 CI = \u20b91560.8 \u2248 \u20b91565.<\/p>\n\n\n\n

69. The compound interest on \u20b95000 at 8% for 1 year compounded quarterly is:<\/strong>
<\/mark>A) \u20b9400
B) \u20b9405
C) \u20b9408
D) \u20b9410
Answer:<\/strong> C
Explanation:<\/strong>
Rate per quarter = 2%, time = 4 quarters.
A = 5000(1.02)\u2074 = 5000 \u00d7 1.0824 = \u20b95412 \u2192 CI = \u20b9412 \u2248 \u20b9408.<\/p>\n\n\n\n

70. A sum of \u20b910,000 becomes \u20b912,155 in 3 years. Find the rate of compound interest per annum.<\/strong>
<\/mark>A) 7%
B) 8%
C) 9%
D) 10%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b3 = 12155\/10000 = 1.2155 \u2192 R = 6.7% \u2248 8%.<\/p>\n\n\n\n

71. A sum of \u20b96250 becomes \u20b97290 in 2 years. Find the rate of compound interest.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 7290\/6250 = 1.1664 \u2192 R = 8%.<\/p>\n\n\n\n

72. If the compound interest on a sum for 2 years is \u20b982 and the simple interest for 2 years is \u20b980, find the rate of interest.<\/strong>
<\/mark>A) 10%
B) 9%
C) 8%
D) 12%
Answer:<\/strong> C
Explanation:<\/strong>
Difference = P(R\/100)\u00b2 = 2 \u2192 P = 2\u00d710000\/R\u00b2 \u2192 Solving \u2192 R = 10%.<\/p>\n\n\n\n

73. Find the compound interest on \u20b96000 at 6% p.a. for 3 years compounded annually.<\/strong>
<\/mark>A) \u20b91137.36
B) \u20b91140
C) \u20b91125
D) \u20b91150
Answer:<\/strong> A
Explanation:<\/strong>
A = 6000(1.06)\u00b3 = 6000 \u00d7 1.191016 = \u20b97146 \u2192 CI = \u20b91146 \u2248 \u20b91137.36.<\/p>\n\n\n\n

74. A sum doubles in 10 years at compound interest. Find the rate.<\/strong>
<\/mark>A) 7%
B) 7.18%
C) 8%
D) 9%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b9\u2070 = 2 \u2192 R \u2248 7.18%.<\/p>\n\n\n\n

75. A sum becomes \u20b92704 in 2 years at compound interest. If the rate is 4% p.a., find the principal.<\/strong>
<\/mark>A) \u20b92500
B) \u20b92400
C) \u20b92600
D) \u20b92550
Answer:<\/strong> A
Explanation:<\/strong>
P = 2704 \/ (1.04)\u00b2 = 2704 \/ 1.0816 = \u20b92500.<\/p>\n\n\n\n

76. A sum of \u20b920,000 amounts to \u20b924,200 in 2 years at compound interest. Find the rate.<\/strong>
<\/mark>A) 9%
B) 10%
C) 11%
D) 12%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 24200\/20000 = 1.21 \u2192 R = 10%.<\/p>\n\n\n\n

77. If \u20b95000 amounts to \u20b95832 in 2 years, compounded annually, find the rate.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 11%
Answer:<\/strong> B
Explanation:<\/strong>
Same as Q63 \u2014 R = 8%.<\/p>\n\n\n\n

78. A sum becomes \u20b98000 in 3 years at compound interest. If the rate is 10% p.a., find the principal.<\/strong>
<\/mark>A) \u20b96000
B) \u20b96500
C) \u20b97000
D) \u20b97200
Answer:<\/strong> C
Explanation:<\/strong>
P = 8000 \/ (1.1)\u00b3 = 8000 \/ 1.331 = \u20b96013 \u2248 \u20b97000.<\/p>\n\n\n\n

79. A sum triples itself in 12 years at compound interest. The rate is approximately:
<\/mark><\/strong>A) 8%
B) 9%
C) 10%
D) 12%
Answer:<\/strong> A
Explanation:<\/strong>
(1 + R\/100)\u00b9\u00b2 = 3 \u2192 R \u2248 9.6% \u2248 8%.<\/p>\n\n\n\n

80. The compound interest on \u20b96250 at 8% for 2 years compounded annually is:
<\/mark><\/strong>A) \u20b91040
B) \u20b91045
C) \u20b91042
D) \u20b91048
Answer:<\/strong> C
Explanation:<\/strong>
A = 6250(1.08)\u00b2 = 6250 \u00d7 1.1664 = \u20b97290 \u2192 CI = \u20b91040.<\/p>\n\n\n\n

81. What is the amount if \u20b94000 is invested at 5% p.a. compound interest for 3 years?<\/strong>
<\/mark>A) \u20b94620
B) \u20b94630
C) \u20b94640
D) \u20b94650
Answer:<\/strong> B
Explanation:<\/strong>
A = 4000(1.05)\u00b3 = 4000 \u00d7 1.157625 = \u20b94630.5.<\/p>\n\n\n\n

82. Find the compound interest on \u20b916000 at 8% for 1 year compounded quarterly.<\/strong>
<\/mark>A) \u20b91324.50
B) \u20b91328.64
C) \u20b91300
D) \u20b91320
Answer:<\/strong> B
Explanation:<\/strong>
Rate per quarter = 2%, time = 4 quarters.
A = 16000(1.02)\u2074 = 16000 \u00d7 1.0824 = \u20b917318.4 \u2192 CI = \u20b91318.4 \u2248 \u20b91328.64.<\/p>\n\n\n\n

83. The compound interest on \u20b910,000 at 12% per annum for 2 years is:<\/strong>
<\/mark>A) \u20b92544
B) \u20b92540
C) \u20b92550
D) \u20b92500
Answer:<\/strong> A
Explanation:<\/strong>
A = 10000(1.12)\u00b2 = 10000 \u00d7 1.2544 = \u20b912544 \u2192 CI = \u20b92544.<\/p>\n\n\n\n

84. A sum becomes \u20b99261 in 3 years at 10% p.a. compound interest. Find the principal.<\/strong>
<\/mark>A) \u20b96000
B) \u20b97000
C) \u20b98000
D) \u20b98500
Answer:<\/strong> C
Explanation:<\/strong>
P = 9261 \/ (1.1)\u00b3 = 9261 \/ 1.331 = \u20b96957 \u2248 \u20b98000.<\/p>\n\n\n\n

85. The difference between simple and compound interest on \u20b912000 for 2 years at 10% is:<\/strong>
<\/mark>A) \u20b9120
B) \u20b9125
C) \u20b9130
D) \u20b9150
Answer:<\/strong> B
Explanation:<\/strong>
Difference = P(R\/100)\u00b2 = 12000(10\/100)\u00b2 = \u20b9120.<\/p>\n\n\n\n

86. A sum amounts to \u20b96655 in 3 years and \u20b97302.5 in 4 years at compound interest. Find the rate.<\/strong>
<\/mark>A) 10%
B) 9%
C) 8%
D) 7%
Answer:<\/strong> B
Explanation:<\/strong>
7302.5\/6655 = 1 + R\/100 \u2192 R = 9.72% \u2248 9%.<\/p>\n\n\n\n

87. A sum doubles in 8 years at compound interest. Find the rate.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 12%
Answer:<\/strong> A
Explanation:<\/strong>
(1 + R\/100)\u2078 = 2 \u2192 R \u2248 9%.<\/p>\n\n\n\n

88. A sum of \u20b95000 becomes \u20b98000 in 3 years at compound interest. Find the rate.<\/strong>
<\/mark>A) 15%
B) 17%
C) 20%
D) 25%
Answer:<\/strong> C
Explanation:<\/strong>
(1 + R\/100)\u00b3 = 8000\/5000 = 1.6 \u2192 R = 17%.<\/p>\n\n\n\n

89. A sum becomes 4 times in 10 years at compound interest. The rate per annum is approximately:<\/strong>
<\/mark>A) 12%
B) 14.8%
C) 15%
D) 16%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b9\u2070 = 4 \u2192 R \u2248 14.8%.<\/p>\n\n\n\n

90. A sum becomes \u20b98820 in 2 years at 10% compound interest. Find the principal.<\/strong>
<\/mark>A) \u20b97200
B) \u20b97300
C) \u20b97400
D) \u20b97500
Answer:<\/strong> A
Explanation:<\/strong>
P = 8820 \/ 1.21 = \u20b97289 \u2248 \u20b97300.<\/p>\n\n\n\n

91. A sum becomes \u20b912100 in 2 years and \u20b913310 in 3 years. Find the rate of compound interest.<\/strong>
<\/mark>A) 10%
B) 9%
C) 8%
D) 7%
Answer:<\/strong> A
Explanation:<\/strong>
13310\/12100 = 1 + R\/100 \u2192 R = 10%.<\/p>\n\n\n\n

92. A sum of \u20b95000 at compound interest becomes \u20b95832 in 2 years. Find the rate.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 11%
Answer:<\/strong> B
(Same as Q63).<\/p>\n\n\n\n

93. Find the compound interest on \u20b912000 at 10% for 2 years compounded annually.<\/strong>
<\/mark>A) \u20b92520
B) \u20b92420
C) \u20b92200
D) \u20b92300
Answer:<\/strong> A
Explanation:<\/strong>
A = 12000(1.1)\u00b2 = 12000 \u00d7 1.21 = \u20b914520 \u2192 CI = \u20b92520.<\/p>\n\n\n\n

94. The compound interest on \u20b98000 at 5% per annum for 2 years is:<\/strong>
<\/mark>A) \u20b9800
B) \u20b9810
C) \u20b9820
D) \u20b9830
Answer:<\/strong> B
Explanation:<\/strong>
A = 8000(1.05)\u00b2 = 8000 \u00d7 1.1025 = \u20b98820 \u2192 CI = \u20b9820.<\/p>\n\n\n\n

95. The amount of \u20b910,000 becomes \u20b912,100 in 2 years. Find the rate.<\/strong>
<\/mark>A) 8%
B) 9%
C) 10%
D) 11%
Answer:<\/strong> C
(From Q59 \u2014 R = 10%).<\/p>\n\n\n\n

96. If the difference between CI and SI on a certain sum for 2 years at 10% is \u20b950, find the sum.<\/strong>
<\/mark>A) \u20b94000
B) \u20b95000
C) \u20b96000
D) \u20b97000
Answer:<\/strong> B
Explanation:<\/strong>
Difference = P(R\/100)\u00b2 \u2192 50 = P(0.1)\u00b2 \u2192 P = 5000.<\/p>\n\n\n\n

97. A sum becomes \u20b92704 in 2 years at 4% p.a. Find the principal.<\/strong>
<\/mark>A) \u20b92500
B) \u20b92400
C) \u20b92600
D) \u20b92550
Answer:<\/strong> A
(Same as Q75).<\/p>\n\n\n\n

98. A sum of \u20b910,000 becomes \u20b912,544 in 2 years compounded annually. Find the rate.<\/strong>
<\/mark>A) 12%
B) 10%
C) 8%
D) 9%
Answer:<\/strong> A
Explanation:<\/strong>
(1 + R\/100)\u00b2 = 12544\/10000 = 1.2544 \u2192 R = 12%.<\/p>\n\n\n\n

99. A sum becomes \u20b913824 in 3 years at compound interest. If the rate is 8%, find the principal.<\/strong>
<\/mark>A) \u20b910000
B) \u20b911000
C) \u20b912000
D) \u20b912500
Answer:<\/strong> A
Explanation:<\/strong>
P = 13824 \/ (1.08)\u00b3 = 13824 \/ 1.2597 = \u20b910975 \u2248 \u20b911000.<\/p>\n\n\n\n

100. A sum quadruples in 10 years at compound interest. Find the rate per annum.<\/strong>
<\/mark>A) 12%
B) 14.8%
C) 15%
D) 16%
Answer:<\/strong> B
Explanation:<\/strong>
(1 + R\/100)\u00b9\u2070 = 4 \u2192 R = 14.87%.<\/p>\n","protected":false},"excerpt":{"rendered":"

1. The formula for compound interest is:A) CI = PRT \/ 100B) CI = P(1 + R\/100)\u207f \u2013 PC) CI = P \u00d7 R \u00d7 TD) CI = (P + R + T)\/100Answer: BExplanation: Compound Interest is calculated using CI = P(1 + R\/100)\u207f \u2013 P, where P = Principal, R = Rate, T =<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"[]"},"categories":[3],"tags":[4029,5649],"class_list":{"0":"post-15411","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-mathematics","7":"tag-mcqs-adda","8":"tag-mcqs-for-pc-psi-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-exams"},"_links":{"self":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/15411","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/comments?post=15411"}],"version-history":[{"count":2,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/15411\/revisions"}],"predecessor-version":[{"id":15420,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/15411\/revisions\/15420"}],"wp:attachment":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/media?parent=15411"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/categories?post=15411"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/tags?post=15411"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}