{"id":9593,"date":"2024-06-28T11:44:52","date_gmt":"2024-06-28T10:44:52","guid":{"rendered":"https:\/\/mcqsadda.com\/?p=9593"},"modified":"2024-07-17T11:58:34","modified_gmt":"2024-07-17T10:58:34","slug":"chemical-bonding-set-1","status":"publish","type":"post","link":"https:\/\/mcqsadda.com\/index.php\/2024\/06\/28\/chemical-bonding-set-1\/","title":{"rendered":"Chemical bonding Set &#8211; 1"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\"><strong>1. \u00a0In the periodic table, the element with atomic number 16 will be placed in the group ___________.<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Third<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. Fourth<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Fifth<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. Sixth<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:D.Sixth<BR>\nSOLUTION : Sixth<\/p>\n<\/div>egin\n\n\n\n<h2 class=\"wp-block-heading\"><strong>2. The group number, number of valence electrons, and valency of an element with the atomic number 15, respectively , are _________.<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. 16, 5 and 2<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B.  15, 5 and 3<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. 16, 6 and 3<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. 15, 6 and 2<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:B.15, 5 and 3<BR>\nSOLUTION:The group number, number of valence electrons, and valency of an element with the atomic number 15 are 15, 5, and 3, respectively. This element is phosphorus.<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>3. Which of the following element will become stable after losing and electron?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. \u00a0\u00a0Helium<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a0\u00a0Iodine<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C.  Sodium<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D.  Oxygen<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER : C.Sodium<BR>\nSOLUTION: SODIUM is the element which would become stable by losing an electron. It becomes an ION in its IONIZATION. As SODIUM loses 1 electron, it is left with (11) protons &#038; (10) electrons. Hydrogen &#038; lithium are also in Group -1 elements with SODIUM.\n <\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>4. Contain 9 Protons, 10 electrons and 11 neutrons . It is __________.<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. A neutral atom<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. An Isotope<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. A cation<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. An anion<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:D.An anion<BR>\nSOLUTION:A species with 9 protons, 10 electrons, and 11 neutrons is an anion with an atomic number of 9 and an electronic configuration of 2,7. This means that the species can easily gain an electron to complete its octet, resulting in 10 electrons and an electron configuration of 2,8. Since the species has one extra electron compared to the number of protons, it has a unit negative charge. \n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>5. \u00a0Which pair of elements belongs to same group?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Elements with atomic no 17 and 38<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. Elements with atomic no 20 and 40<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Elements with atomic no 17 and 53 <\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. Elements with atomic no 11 and 33<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:C.Elements with atomic no 17 and 53  <BR>\nSOLUTION:In conclusion, the correct pair of elements that belongs to the same group is &#8220;Elements with atomic no. 17 and 53&#8221; (Chlorine and Iodine).\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>6. \u00a0What is the total number of electrons in the Chlorine molecule?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. \u00a017<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a034<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. 18<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. 16<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:A.17<BR>\nSOLUTION:Atomic number of Cl is 17. So, its neutral atom contains 17 electrons as it&#8217;s nucleus contains 17 protons. Cl- anion more one electron. That means, Cl- contains total 18 electrons. \n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>7. Which among the following is not a property of ionic bond?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Losing of electrons<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. Gain of electrons<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Sharing of electrons<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. Transfer of electrons<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:C.Sharing of electrons<BR>\nSOLUTION :\nThe property from the options which does not describe an ionic bond is: Sharing of electrons.\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>8. \u00a0 The reason of bonding in ionic compounds is ________.<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Sharing of electrons<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a0Repulsion force<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Attraction force<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. None of these<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER: C.Attraction force<BR>\nSOLUTION: Attraction force\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>9. A molecule of _______ Contains a triple bond.<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Sulphur<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a0Nitrogen<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Carbon<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. Oxygen<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:B.Nitrogen<BR>\nSOLUTION: A nitrogen molecule (N2) contains a triple covalent bond between two nitrogen atoms.\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>10. \u00a0Which of the following is not a typical property of an ionic compound?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. High melting point<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a0Conducts electricity in the molten and in the aqueous solution state<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. They are soluble in water <\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. <strong>They are insoluble in water <\/strong><\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER: D.They are insoluble in water <BR>\nSOLUTION:\nInsolubility in water is not a typical property of an ionic compound. In fact, ionic compounds are usually soluble in water.\n<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>1. \u00a0In the periodic table, the element with atomic number 16 will be placed in the group ___________. A. Third B. Fourth C. Fifth D. Sixth ANSWER &#038; SOLUTION ANSWER:D.Sixth SOLUTION : Sixth egin 2. The group number, number of valence electrons, and valency of an element with the atomic number 15, respectively , are<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[9,19],"tags":[5067,5651,5653,5062,5646,5059,4029,5649,5652,5060,5066,5064,5065,5061,5068,5063],"class_list":{"0":"post-9593","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-chemistry","7":"category-science","8":"tag-a-molecule-of-_______-contains-a-triple-bond","9":"tag-chemistry-mcqs-for-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-exams","10":"tag-chemistry-mcqs-for-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-examsin-kannada","11":"tag-contain-9-protons-10-electrons-and-11-neutrons-it-is-__________","12":"tag-exam-veda","13":"tag-in-the-periodic-table-the-element-with-atomic-number-16-will-be-placed-in-the-group-___________","14":"tag-mcqs-adda","15":"tag-mcqs-for-pc-psi-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-exams","16":"tag-mcqs-for-pc-psi-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-examsin-kannada","17":"tag-the-group-number-number-of-valence-electrons-and-valency-of-an-element-with-the-atomic-number-15-respectively-are-_________","18":"tag-the-reason-of-bonding-in-ionic-compounds-is-________","19":"tag-what-is-the-total-number-of-electrons-in-the-chlorine-molecule","20":"tag-which-among-the-following-is-not-a-property-of-ionic-bond","21":"tag-which-of-the-following-element-will-become-stable-after-losing-and-electron","22":"tag-which-of-the-following-is-not-a-typical-property-of-an-ionic-compound","23":"tag-which-pair-of-elements-belongs-to-same-group"},"_links":{"self":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/9593","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/comments?post=9593"}],"version-history":[{"count":4,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/9593\/revisions"}],"predecessor-version":[{"id":9616,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/9593\/revisions\/9616"}],"wp:attachment":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/media?parent=9593"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/categories?post=9593"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/tags?post=9593"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}