{"id":9670,"date":"2024-07-01T05:26:30","date_gmt":"2024-07-01T04:26:30","guid":{"rendered":"https:\/\/mcqsadda.com\/?p=9670"},"modified":"2024-07-17T11:58:21","modified_gmt":"2024-07-17T10:58:21","slug":"periodic-classification-of-element-set-1","status":"publish","type":"post","link":"https:\/\/mcqsadda.com\/index.php\/2024\/07\/01\/periodic-classification-of-element-set-1\/","title":{"rendered":"Periodic classification of element Set &#8211; 1"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\"><strong>1. \u00a0Which group was added in Mendeleev&#8217;s periodic table?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A.  l group<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B.  Vll group<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C.  Zero group <\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. V group<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:C.Zero group <BR>\nSOLUTION : Later (1902), Mendeleev accepted the evidence for their existence, and they could be placed in a new &#8220;group 0&#8221;, consistently and without breaking the periodic table principle.<\/p>\n<\/div>egin\n\n\n\n<h2 class=\"wp-block-heading\"><strong>2. Name the most electronegative element of Periodic table?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Chlorine<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B.  Bromine<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Fluorine<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. Iodine<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:C.Fluorine<BR>\nSOLUTION:The most electronegative element is fluorine. The least electronegative or most electropositive element is francium.<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>3. Out of F and Cl, which has higher electron affinity?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. \u00a0\u00a0CI<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a0\u00a0F<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Both have same<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D.  None<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER : A.CI<BR>\nSOLUTION: Chlorine (Cl) has a higher electron affinity than fluorine (F).\n <\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>4. The element with atomic number 9 resembles the element with atomic number __________.<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. 35<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. 27<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. 17<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. 8<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:C.17<BR>\nSOLUTION:From the above discussion we can say that the element with atomic number 9 (Fluorine) will show properties similar to the element with atomic number 17 (chlorine) because both are halogens.\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>5. \u00a0Why N is more electronegative than Phosphorous?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Because it has less mass than Phosphorous<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. Because it has half filled valence shell<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Because it forms so many compounds<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. Because it has small size than Phosphorous<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:D.Because it has small size than Phosphorous <BR>\nSOLUTION:The element nitrogen will be more electronegative because of the smaller size of its atom compared to phosphorus. Since nitrogen has a smaller atomic radius than phosphorus, the attraction of its nucleus towards the incoming electron is more than phosphorus. Therefore, nitrogen accepts electrons more easily.\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>6. \u00a0In the periodic table , zig zag lines separate metals from non metals, what is called ?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. \u00a0Metalloids<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a0Lanthanoids<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Actinoids<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. Diagonal relationship<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:A.Metalloids<BR>\nSOLUTION:The zig-zag line on the periodic table that separates metals from non-metals is also known as the metalloid line. The elements that touch the line are called metalloids or semimetals. These elements have properties that fall between those of metals and non-metals.\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>7. Write the formula to find the maximum number of eletrons that shell can accommodate<\/strong>_________.<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. 2n<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. 4(n)2<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. 2n2<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. 4n<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:C.2n2<BR>\nSOLUTION :\nThe maximum number of electrons that can be filled in an orbit (shell) can be found by using the formula 2n2; where &#8216;n&#8217; stands for an orbit&#8217;s serial number.\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>8. \u00a0 Predict the position of Fluorine ________.<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. 17th group , 2nd period<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a018th group, 2nd period<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. 17th group, 3rd period<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. 7th group, 2nd period<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER: A.17th group , 2nd period<BR>\nSOLUTION: Fluorine is an element on the periodic table. It is the first element in group 17. It is located in the 3rd period in the 17th group.\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>9. Name the element with only 4 electrons in valence shell________.<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. C<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a0Ge<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Si<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. Al<\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER:A.C<BR>\nSOLUTION: Carbon (C) is the element with four electrons in its valence shell.\n<\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>10. \u00a0Which element has twice as many as electrons in first shell ?<\/strong><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Si<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. \u00a0Ge<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. N<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>D. <strong>C<\/strong><\/strong><\/h3>\n\n\n\n<button class=\"acc\">ANSWER &#038; SOLUTION<\/button>\n<div class=\"pnl\">\n  <p>ANSWER: D.C <BR>\nSOLUTION:\nThe element which has twice as many electrons in its second shell as in the first shell is carbon.\n<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>1. \u00a0Which group was added in Mendeleev&#8217;s periodic table? A. l group B. Vll group C. Zero group D. V group ANSWER &#038; SOLUTION ANSWER:C.Zero group SOLUTION : Later (1902), Mendeleev accepted the evidence for their existence, and they could be placed in a new &#8220;group 0&#8221;, consistently and without breaking the periodic table principle.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[9,19],"tags":[5651,5653,5646,4029,5649,5652,5088,5081,5082,5087,5083,5089,5080,5084,5086],"class_list":{"0":"post-9670","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-chemistry","7":"category-science","8":"tag-chemistry-mcqs-for-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-exams","9":"tag-chemistry-mcqs-for-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-examsin-kannada","10":"tag-exam-veda","11":"tag-mcqs-adda","12":"tag-mcqs-for-pc-psi-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-exams","13":"tag-mcqs-for-pc-psi-sda-fda-pdo-vao-banking-kas-ias-ssc-gd-ssc-chsl-ssc-cgl-for-all-compitative-examsin-kannada","14":"tag-name-the-element-with-only-4-electrons-in-valence-shell________","15":"tag-name-the-most-electronegative-element-of-periodic-table","16":"tag-out-of-f-and-cl-which-has-higher-electron-affinity","17":"tag-predict-the-position-of-fluorine-________","18":"tag-the-element-with-atomic-number-9-resembles-the-element-with-atomic-number-__________","19":"tag-which-element-has-twice-as-many-as-electrons-in-first-shell","20":"tag-which-group-was-added-in-mendeleevs-periodic-table","21":"tag-why-n-is-more-electronegative-than-phosphorous","22":"tag-write-the-formula-to-find-the-maximum-number-of-eletrons-that-shell-can-accommodate_________"},"_links":{"self":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/9670","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/comments?post=9670"}],"version-history":[{"count":2,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/9670\/revisions"}],"predecessor-version":[{"id":9690,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/posts\/9670\/revisions\/9690"}],"wp:attachment":[{"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/media?parent=9670"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/categories?post=9670"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mcqsadda.com\/index.php\/wp-json\/wp\/v2\/tags?post=9670"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}